Kindly answer 1 a,b & c 1. Concentration- time data for the conversion of A and B to D are listed in the tablebelow:ExperimentTime (s)[A][B][C][D]15.002.001.000.00604.801.901.000.10210.002.001.000.00609.601.801.000.205.004.001.000.00604.803.901.000.105.002.002.000.00604.601.802.000.20a) Write a balanced equation for the reaction.b) Describe the reaction order with respect to A, B and C and the overall reactionorder.c) State the rate law.d) Explain about the catalyst used in this reaction.e) Calculate the rate constant for the formation of D.

Analyse the data given and the basis of it propose a suitable balanced reaction.

Answered: 1. Concentration- time data for the…

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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how we can calculate the actual dissolved Oxygen concentration (cL) in oxygen transfer rate (OTR) formula .whenwe have cL than we can calculate the KLa value we find OTR from graph slope . cS =468/(31.6+T) T= 23 KLa = OTR/(cL- cS) cS = oxygen saturation concentration time(h) Dissolved oxygen(mg/l) 3.264 4.326 3.2818 3.697 3.29537 3.674 3.31445 3.268 3.33385 2.858 3.35218 2.475 3.37633 1.994 3.42174 1.15 3.4376 0.89 3.48951 0.249 3.54265 0.028
NH4+ {aq) + NO2(aq) -> N2(g) +2H2O{l} Data Initial [NH4+] Initial [NO2-] rate 1 0.0100 0.200 5.4 x10-7 2 0.0200 0.200 10.8x10-7 3 0.0400 0.200 21.5x10-7 4 0.200 0.0202 10.8x10-7 5 0.200 0.0404 21.6x10-7 6 0.200 0.0808 43.3x10-7 Find x,y,k
Faat pls i will give u like for sure solve this question correctly in 5 min pls
General Chemistry for Engineers Lesson: Chemical Kinetics Directions: Answer the following problems by showing the complete solution. In return, I will give you a good and high rating. Thank you so much! Note: Please input the units and measurements in the calculations. Thank you so much! Number 19 and 20
Plot on to graph moles of S2O8 vs time to achieve M/s. The initial concentration of S2O8: 0.05M (added is 2.5mL of 0.200M, but it was diluted so 0.200 x 2.5/10mL = 0.05M). Below is the time (s) and moles consumed. 188s - 0.00002 moles 362s - 0.00004 moles 548s - 0.00006 moles 740s - 0.00008 moles 1001s - 0.0001 moles I was told to plot concentration vs time then subtract the moles, but I'm confused how to do that.
Choices for slope: a. -1.35 x 10^4 b. 1.35 x 10^4 c. -1.09 x 10^4 d. 1.09 x 10^4 choices for y intercept: a. -27.8 b. 27.8 c. 37.4 d. -37.4 choices for pearson: a. -0.962 b. -1000 c. -0.982 activation energy a. 9.06 x 10^4 b. 113 c. 90.65 collision frequency factor A a. 1.15 x 10^12 b. 113 c. 90.65
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Table 2: Molarity of H2O2 and KI and Reaction Rate Trial H2O2 Concentration, M KI Concentration, M Reaction Rate(Reciprocal Slope) 1 0.29 M 0.40 M 14.08 2 0.29 M 0.20M 25 3 0.023 M 0.40 M 20 Rate constant value Trial 1 ______________ Trial 2 ______________ Trial 3 ______________ Average _____________
In Experiment 4- Chemical Kinetics “The Rate of Chemical Reaction”, the following data were obtained: Rxn Mixture time(s) temperature (˚C) 1 190 23.0 2 378 23.0 3 97 23.0 4 205 23.0 5 44 23.0 6 90 35.0 Concentrations and portions for reaction mixture number one: H2O 0.050 M Buffer 0.050 M KI (mL) 0.1% Starch (mL) 0.0450 MNa2S2O3(mL) 0.8525 M H202 (mL) 75.0mL 30.0mL 25.0 5.00 5.00 10.00 Use the data above to answer the following questions where applicable. (a) Write the formulas of the reactants, there are three, in the reaction being studied.Signs + or - or subscripts may be entered all on the same line; S2O32- can be entered as S2O3^2-, the symbol, ^, is not required if the…
Table 2: Molarity of H2O2 and KI and Reaction Rate Trial H2O2 Concentration, M KI Concentration, M Reaction Rate(Reciprocal Slope) 1 0.29 M 0.40 M 14.08 2 0.29 M 0.20M 25 3 0.023 M 0.40 M 20 Order with respect to H2O2: -0.138 Order with respect to KI: -0.828 Rate constant value Trial 1: 5.84 Trial 2: 5.55 Trial 3: 5.56 Average: 5.6 -Please help me with this part, please 1. Should the rate constant (k) be the same for all three trials in this experiment? Explain your answer. 2.Write the complete rate law for this reaction.
Table 2: Molarity of H2O2 and KI and Reaction Rate Trial H2O2 Concentration, M KI Concentration, M Reaction Rate(Reciprocal Slope) 1 0.29 M 0.40 M 14.08 2 0.29 M 0.20M 25 3 0.023 M 0.40 M 20 please help me with this part Rate constant value Trial 1 ______________ Trial 2 ______________ Trial 3 ______________ Average _____________
The line weaver Burk plot allows the relationship between reaction velocity and substrate concentration to be calculated as a ____________ instead of a hyperbola.

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