1. In figure (1), shows a uniform beam subjected to a linear increasing distributed load. The equation for the resulting elastic curve is: w y = 120EIL (-x5+2L²x3 - L*x) Using the numerical methods to determine the point of max. deflection (that is, the value of x where "Y-0. Then substitute dx this value in the given equation to find the value of maximum deflection. Using the following parameter values in your computations: L = 600cm; E50000 k N/cm2;I= 30000cmt and w =2.5 k N/cm. (a) r=Ly- 0) =0, v= 0) (b) Figure (1)

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter9: Deflections Of Beams
Section: Chapter Questions
Problem 9.4.7P: -7 A beam on simple supports is subjected to a parabolically distributed load of intensity q(x) =...
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1. In figure (1), shows a uniform beam subjected to a linear increasing distributed load. The equation for the resulting elastic
curve is:
w
y =
120EIL
(-x5+2L?x3 - L*x)
Using the numerical methods to determine the point of max. deflection (that is, the value of x where "Y 0. Then substitute
dx
this value in the given equation to find the value of maximum deflection. Using the following parameter values in your
computations:
L = 600cm; E50000 k N/cm2;1=30000cm* and w =2.5k N/cm.
(a)
r Ly 0)
=0, v- 0)
(b)
Figure (1)
Transcribed Image Text:1. In figure (1), shows a uniform beam subjected to a linear increasing distributed load. The equation for the resulting elastic curve is: w y = 120EIL (-x5+2L?x3 - L*x) Using the numerical methods to determine the point of max. deflection (that is, the value of x where "Y 0. Then substitute dx this value in the given equation to find the value of maximum deflection. Using the following parameter values in your computations: L = 600cm; E50000 k N/cm2;1=30000cm* and w =2.5k N/cm. (a) r Ly 0) =0, v- 0) (b) Figure (1)
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