4. The solution of the HMOs for the allyl cation gives the following in order of increasing electronic energy: H₂C + CH2 ¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03 ¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3 = - Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03 Given these solutions, draw the three MOs with the correct phases and relative sizes. (10 points)

Organic Chemistry
8th Edition
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Chapter14: Mass Spectrometry
Section: Chapter Questions
Problem 14.13P
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4. The solution of the HMOs for the allyl cation gives the following in order of
increasing electronic energy:
H₂C
+
CH2
¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03
¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3
=
-
Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03
Given these solutions, draw the three MOs with the correct phases and relative
sizes. (10 points)
Transcribed Image Text:4. The solution of the HMOs for the allyl cation gives the following in order of increasing electronic energy: H₂C + CH2 ¥₁ = (1/2) 1 + [1/(SQRT 2)] 2 + (1/2) 03 ¥2 = [1/(SQRT 2)] 1 - [1/(SQRT 2)] $3 = - Y3 (1/2) 01 [1/(SQRT 2)] 2 + (1/2) 03 Given these solutions, draw the three MOs with the correct phases and relative sizes. (10 points)
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