6. Indicate whether each of the following events occurs when tryptophan is high or when tryptophan is low by placing a check in each of the appropriate blanks. Share your reasoning. Tryptophan Tryp high Event Ribosome does not stall at Trp codons Region 2 of the leader pairs with region 3 Ribosome covers part of region 2 of leader Transcription is terminated before structural genes are transcribed

6. Indicate whether each of the following events occurs when tryptophan is high or when tryptophan is low by placing a check in each of the appropriate blanks. Share your reasoning. Tryptophan Tryp high Event Ribosome does not stall at Trp codons Region 2 of the leader pairs with region 3 Ribosome covers part of region 2 of leader Transcription is terminated before structural genes are transcribed

Human Anatomy & Physiology (11th Edition)

11th Edition

ISBN:9780134580999

Author:Elaine N. Marieb, Katja N. Hoehn

Publisher:Elaine N. Marieb, Katja N. Hoehn

Chapter1: The Human Body: An Orientation

Section: Chapter Questions

Problem 1RQ: The correct sequence of levels forming the structural hierarchy is A. (a) organ, organ system,...

See similar textbooks

Similar questions

1. The location of hemophilia C- factor XI is 4q35, where exactly is it? Describe.2. Referring to image of chromosome 16 provided, indicate the exact location of the geneslabeled a-k:
(1) Why the ratio of PE/GFP fluorescence is measured in the FACS experiment, instead of measuring only total PE fluorescence? (2) Explain the effect that each mutation causes in the function of MC4R, and how they can be linked to disease.
For each of the E. coli strains that follow, indicate theeffect of the genotype on the expression of the trpEand trpC genes in the presence or absence of tryptophan. [In the wild type (R+ P+ o+ att+ trpE+ trpC+),trpC and trpE are fully repressed in the presence oftryptophan and are fully expressed in the absence oftryptophan.]R = repressor gene; Rnproduct cannot bind tryptophan; R− product cannot bind operatoro = operator for the trp operon; o− cannot bind repressoratt = attenuator; att− is a deletion of the attenuatorP = promoter; P− is a deletion of the trp operonpromotertrpE− and trpC− are null (loss-of-function) mutationsa. R+ P− o+ att+ trpE+ trpC+b. R− P+ o+ att+ trpE+ trpC+c. RnP+ o+ att+ trpE+ trpC+d. R− P+ o+ att− trpE+ trpC+e. R+ P+ o− att+ trpE+ trpC−/R− P+ o+ att+trpE− trpC+f. R+ P− o+ att+ trpE+ trpC−/R− P+ o+ att+trpE− trpC+g. R+ P+ o− att− trpE+ trpC−/R− P+ o− att+trpE− trpC+
Some people have a genetic predisposition for developing priondiseases. Examples are described in Table 25.6. In the case ofGerstmann-Straüssler-Scheinker disease, the age of onset istypically 30–50 years, and the duration of the disease (whichleads to death) is about 5 years. Suggest a possible explanationwhy someone can live for a relatively long time withoutsymptoms and then succumb to the disease in a relativelyshort time.
In the Western blot shown here, proteins were isolated from redblood cells and muscle cells from two different individuals. Oneindividual was unaffected, and the other suffered from a diseaseknown as thalassemia, which involves a defect in hemoglobin. Theblot was exposed to an antibody that recognizes β globin, whichis one of the polypeptides that constitute hemoglobin. Equal totalamounts of cellular proteins were added to each lane. Explain these results.
Utilizing Hind III and EcoR V Restriction Enzyme with Pet41 and the following gene of interest... a tgaaacaaca aaaacggctt tacgcccgat tgctgacgct gttatttgcg 61 ctcatcttct tgctgcctca ttctgcagca gcggcggcaa atcttaatgg gacgctgatg 121 cagtattttg aatggtacat gcccaatgac ggccaacatt ggaagcgttt gcaaaacgac 181 tcggcatatt tggctgaaca cggtattact gccgtctgga ttcccccggc atataaggga 241 acgagccaag cggatgtggg ctacggtgct tacgaccttt atgatttagg ggagtttcat 301 caaaaaggga cggttcggac aaagtacggc acaaaaggag agctgcaatc tgcgatcaaa 361 agtcttcatt cccgcgacat taacgtttac ggggatgtgg tcatcaacca caaaggcggc 421 gctgatgcga ccgaagatgt aaccgcggtt gaagtcgatc ccgctgaccg caaccgcgta 481 atttcaggag aacacctaat taaagcctgg acacattttc attttccggg gcgcggcagc 541 acatacagcg attttaaatg gcattggtac cattttgacg gaaccgattg ggacgagtcc 601 cgaaagctga accgcatcta taagtttcaa ggaaaggctt gggattggga agtttccaat 661 gaaaacggca actatgatta tttgatgtat gccgacatcg attatgacca tcctgatgtc 721 gcagcagaaa ttaagagatg gggcacttgg tatgccaatg aactgcaatt ggacggtttc 781…
Of all the genes in the human genome, the ones withthe most characterized Alu insertions are those thatcause hemophilia, including several insertions in thefactor VIII and factor IX genes. Based on this fact, yourcolleague hypothesizes that the Alu element prefers toinsert into these genes. Do you agree? What other reason can you provide that also explains these data?
1. Suggest which restriction enzyme (RE) sites that have been chosen to insert the Lm-pgam gene in pET-28a vector. Justify your decision
The pathway for arginine biosynthesis in Neurosporacrassa involves several enzymes that produce a seriesof intermediates.ARG-E ARG-F ARG-G ARG-HN-acetylornithine → ornithine → citrulline → argininosuccinate → argininea. If you did a cross between ARG-E− and ARG-H−Neurospora strains, what would be the distributionof Arg+ and Arg− spores within parental ditype andnonparental ditype asci? Give the spore types inthe order in which they would appear in the ascus.b. For each of the spores in your answer to part (a),what nutrients could you supply in the media to getspore growth?
6_c. In cancerous cells, CpG islands are: where intercalating agents are found demethylated methylated.
An ade+ arg+ cys+ his+ leu+ pro+ bacterial strain is knownto be lysogenic for a newly discovered phage, but the siteof the prophage is not known. The bacterial map isleucysarghisadeproThe lysogenic strain is used as a source of the phage, andthe phages are added to a bacterial strain of genotypeade- arg- cys- his- leu- pro-. After a short incubation,samples of these bacteria are plated on six differentmedia, with the supplementations indicated in thefollowing table. The table also shows whether colonieswere observed on the various media.PresenceMedium Ade Arg Cys His Leu Pro of colonies1 - + + + + + N2 + - + + + + N3 + + - + + + C4 + + + - + + N5 + + + + - + C6 + + + + + - NNutrient supplementation in medium(In this table, a plus sign indicates the presence of anutrient supplement, a minus sign indicates that asupplement is not present, N indicates no colonies, and Cindicates colonies present.)a. What genetic process is at work here?b. What is the approximate locus of the prophage?
6. A diploid strain of yeast was made by mating a haploidstrain with a genotype w−, x−, y−, and z− with a haploidstrain of opposite mating type that is wild type for thesefour genes. The diploid strain was phenotypically wildtype. Four different X-ray-induced diploid mutantswith the following phenotypes were produced fromthis diploid yeast strain. Assume a single new mutation is present in each strain.Strain 1 w− x+ y− z+Strain 2 w+ x− y− z−Strain 3 w− x+ y− z−Strain 4 w− x+ y+ z+When these mutant diploid strains of yeast go throughmeiosis, each ascus is found to contain only two viablehaploid spores.a. What kind of mutations were induced by X-rays tomake the listed diploid strains?b. Why did two spores in each ascus die?