A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 19.13 mL of 0.04842 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F- to mask the Al3+. To the 50.00 mL sample, 25.00 mL of 0.04842 M EDTA was added. The excess EDTA was then titrated with 0.02147 M Mn2+. A total of 21.1 mL was required to reach the methylthymol blue end point. Determine pAl3+ and pPb2+ in the unknown sample. PA3+ pPb2+
A 25.00 mL sample containing an unknown amount of Al3+ and Pb2+ required 19.13 mL of 0.04842 M EDTA to reach the end point. A 50.00 mL sample of the unknown was then treated with F- to mask the Al3+. To the 50.00 mL sample, 25.00 mL of 0.04842 M EDTA was added. The excess EDTA was then titrated with 0.02147 M Mn2+. A total of 21.1 mL was required to reach the methylthymol blue end point. Determine pAl3+ and pPb2+ in the unknown sample. PA3+ pPb2+
Chapter17: Complexation And Precipitation Reactions And Titrations
Section: Chapter Questions
Problem 17.31QAP
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