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- If a 35.0-mL water sample required 10.25 mL of 0.0150 M EDTA solution to reach equivalence point, what’s the hardness of the water sample in ppm CaCO3 (FW 100.1 g/mol)?A 5.00 mL tap water sample was measured out with a volumetric pipette, and added to a 25 mL Erlenmeyer flask. It was then titrated with a 0.0100 M Na2EDTA.2H2O solution, and found to take 0.635 mL of the EDTA solution to reach the blue endpoint.. 100 ml boiled cooled and filtered water sample takes 9.6 ml of M/50 EDTA in titration. The Permanent hardness of the water sample in terms of ppm of CaCO3 equivalent is
- If you titrate 50 mL of a sample with 0.06 N EDTA and the titration takes 12.4 mL of EDTA to reach the endpoint, what is the hardness of the sample in ppm as CaCO3?Identify the nature of the water sample from the hardness value.A sample of water from a river was analyzed by titrating a 125 mL aliquot with 0.0210 M EDTA, consuming 22.52 mL. Express the hardness of the water in ppm of CaCO3.10) 1.0 gram of CaCO3 was dissolved in HCl and the solution was made up to 1000 ml with distilled water. 50 ml of the solution required 45 ml of EDTA solution for titration, 50 ml of hard water sample required 28 ml of EDTA and after boiling and filtering required 15 ml of EDTA solution. Calculate Temporary Hardness. A. 288.6 ppmB. 166.6 ppmC. 88.6ppm 11) Calculate the Permanent Hardness for No. 10 A. 111 ppmB. 222 ppmC. 333 ppm 12) Calculate the Total Hardness for No. 10 A. 421.6 ppmB. 621.6 ppmC. 521.6 ppm
- 60 ml of standard hardness containing 1 mg of pure CaCO3 per ml consumed 22 ml of EDTA. 40 ml of water sample consumed 20 ml of EDTA solution using EBT indicator. 40 ml of water sample after boiling, filtering consumed 15 ml of EDTA. Calculate the temporary and permanent hardness of water sample.An EDTA solution prepared from its disodium salt was standardized using 0.250-g primary standard CaCO3 (MW=100.087) and consumed 28.50 mL of the solution. The standard solution was used to determine the hardness of a 2.0 L sample of mineral water, which required 35.57 mL EDTA solution. Express the analysis in terms of ppm CaCO3A 50.0 mL of 3.1% (w/v, g/mL) NaOH solution is mixed with 40.00 mL of 1.2% (w/v, g/mL) Na2CO3 solution. What volume of 0.087 M HCl will be required to titrate the resultant solution to bromocresol green indicator end point (Bcg pH transition range 3.8-5.4, Fwt of NaOH=40 g/mol, Na2CO3= 105.99 g/mol).
- The Kjedahl procedure was used to analyze 256 µL of a solution containing 37.9 mg protein/mL. The liberated NH3 was collected in 5.00 mL of 0.033 6 M HCl, and the remaining acid required 6.34 mL of 0.010 M NaOH for complete titration. What is the weight percent of nitrogen in the protein? wt%List the advantages and disadvantages of a potentiometric titration relative to a direct potentiometricmeasurement.25.00 mL aliquots of the solution in problem 1 are titrated with EDTA to the calmagite end point. A blank containing a small measured amount of Mg^2+ requires 2.12 mL of the EDTA to reach the end point. An aliquot to which the same amount of Mg^2+ is added requires 25.88 mL of the EDTA to reach the end point.