A red die and a blue die are thrown. Both dice are loaded (that is, not all sides are equally likely). Onthe red die, rolling a 3 is half as likely as rolling each of the other five numbers. On the blue die,rolling each even number is twice as likely as rolling each odd number.For each of the following questions, you should write your answer as an expression. Do not give thefinal numeric value. For example, you should write C(4,2)/24) instead of 0.375. What is the probability that the sum of the numbers on the two dice is equal to 5?

Step 1: Step 2: Step 3: Step 4:

Answered: A red die and a blue die are thrown.…

Operations Research : Applications and Algorithms

4th Edition

ISBN:9780534380588

Author:Wayne L. Winston

Publisher:Wayne L. Winston

Chapter23: Simulation With The Excel Add-in @risk

Section: Chapter Questions

Problem 6RP

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Suppose you can buy chocolate bars from a vending machine for $1 each.Inside every chocolate bar is a coupon. You can redeem 7 coupons for 1chocolate bar from the machine.For example, if you have $20, you can initially buy 20 chocolate bars.This gives you 20 coupons. You can redeem 14 coupons for 2 additionalchocolate bars. These 2 chocolate bars have 2 more coupons, so you now have atotal of 8 coupons. This gives you enough to redeem for 1 final chocolate bar.Write a recursive function that would accept the amount of dollars andcoupons as its parameters and output the total number of chocolate bars thatcan be bought (including those redeemed via coupons).Write a test program in C++that would allow the user to enter amount of dollarsand then use the recursive function to compute the number of chocolate barsthe user can buy, and output the number to the screen.
a) In the Hi-Lo game, the player begins with a score of 1000. The player is prompted for the number of points to risk and a second prompt asks the player to choose either High or Low. The player’s choice of either High or Low is compared to a random number between 1 and 13, inclusive. If the number is between 1 and 6 inclusive, then it is considered “low”. A number between 8 and 13 inclusive is “high”. The number 7 is neither high nor low, and the player loses the points at risk. If the player had guessed correctly, the points at risk are doubled and added to the total points. For a wrong choice, the player loses the points at risk. Create a HiLo application based on this specification. Application output should look similar to b) Modify the application to allow the player to continue until there are 0 points left. At the end of the game, display the number of guesses the user took before running out of points.
In this program, you will check whether two dominoes match. Because you can flip a tile, two tiles match if the number on the left or right matches the left or right on the other tile. You should print all matches. First check a direct match, then try flipping tiles. But don’t flip a tile whose left and right numbers are the same. If there is no match, print "No match". For example, with the tiles 1 3 and 4 3, print 1 3 3 4 Three of my tests are failing since there are duplicates of the print results. How would I go about to remove the duplicate?
a) In the Hi-Lo game, the player begins with a score of 1000. The player is prompted for the number of points to risk and a second prompt asks the player to choose either High or Low. The player’s choice of either High or Low is compared to random number between 1 and 13, inclusive. If the number is between 1 and 6 inclusive, then it is considered “low”. A number between 8 and 13 inclusive is “high”. The number 7 is neither high nor low, and the player loses the points at risk. If the player had guessed correctly, the points at risk are doubled and added to the total points. For a wrong choice, the player loses the points at risk. Create a HiLo application based on this specification. Application output should look similar to: b) Modify the application to allow the player to continue until there are 0 points left. At the end of the game, display the number of guesses the user took before running out of points. This is my code I just need part b import java.util.Random; import…
plz solve it asap ????????: Write a program for a game that consists of two players. The rule of the game is that player 1 inputs a random number from 1-100. Player 2 will input 5 numbers. If the summation of those numbers is equal to the number OR less than or greater than the number by 3 (+3 or -3), then player 2 wins. Otherwise, player 1 wins. Test Case 1 Input Player 1, enter a number: 50 Player 2, enter a number: 10 Player 2, enter a number: 10 Player 2, enter a number: 20 Player 2, enter a number: 5 Player 2, enter a number: 7 Output Player 2 wins Explanation: The summation of 10,10,20,5 and 7 is 52 which is greater than 50 by 2. According to the rule, player 2 wins. Test Case 2 Input Player 1, enter a number: 50 Player 2, enter a number: 10 Player 2, enter a number: 10 Player 2, enter a number: 20 Player 2, enter a number: 5 Player 2, enter a number: 1 Output Player 1 wins Explanation: The summation of 10,10,20,5 and 1 is 46 which is less than 50 and also doesn’t…
Can someone please fix the error, the error is that my else statement isn't working in this scenario.
U is upward, D is downward, L is left and R is right : Using the methods pickDir() and exractInt() as shown below, to write a simple automated game: how long does it take a robot to travel from a left line of a field to the right line? Assume field is 15 units apart (meters, kilometers, it doesn’t matter), and the robot starts on the left line. pickDir(): // return string with random direction and random distance (within maxDist) public static String pickDir (int maxDist) { Random r = new Random(); // random number generator // return direction + distance return ( "" + "LRUD".charAt( r.nextInt(4) ) + (r.nextInt(maxDist) + 1) ); } extractInt(): // returns integer from string, from pos p1 to p2: str = "D1" – extractInt(str,1,1); public static int extractInt (String str, int p1, int p2) { return ( Integer.parseInt( str.substring(p1, p2+1) ) ); } Write the main() method that keeps looping until the robot’s random left…
Write a program that will figure out the required change for a purchase. Start by asking the user for the price of the product and the amount paid. (We are expecting that the user will give a larger value for the amount paid.) Read in each of these values as a double. Report back to the user the number of each denomination of change due. You are not just telling the user the amount of money he gets back. Hint: Working with integers is much easier. The modulo operator is your friend for this assignment. Also, note that pennies can be tricky due to the poor real number to binary conversions. (Remember that 1.00 could actually be stored as 0.9999999999997.) Do not include five-dollar bills, ten-dollar bills, etc. Only show coins and one-dollar bill amounts. Be sure to test multiple values. There is a test case below. Your program should run the test case exactly as it appears below, and should work on any other case in general. Output Example (User input is marked with >>>.…
This is my code for a random guess game and whoever has the shortest distance to number 21 wins the game. I need help with looping this game so that it would show these things:Numbers of hands played:Dealer Wins: Player Wins:and if the player randon guess is 21 the code would then exit and say thanks for playing. import random win = 21 dealer = 50 print('Player pick a number between 1-100') guess = random.randint(0,100) print('Player Guess:') print(guess) dealerdist = abs(dealer-win) playerdist = abs(guess-win) if (playerdist > dealerdist): print('Dealer Wins!') if (playerdist < dealerdist): print('Player Wins!')
This is basically something that has a certain number of states (sort of like how a traffic light can be Red, Yellow, Green) and changes from one state to another.This program will have 4 states: HAPPY, HUNGRY, BORED, SAD. Here are the rules. Our animal starts in a state of Happy, with the values for hungry = 0 and bored = 0. Each round the player can "feed", "play" or "ignore" their animal. If they feed their animal, then the hungry meter goes down and bored meter goes up. If they play with their animal, then the bored meter goes down and the hungry meter goes up. If they ignore their animal, then both hungry and bored go up. Don't go below 0 Here are the state changes. Each one of these is a "case" in a switch (from current state -> new State):HAPPY If hungry >= 2 transition to HUNGRY If bored >= 2 transition to BORED HUNGRY if hungry >= 4 transition to SAD if bored > hungry transition to BORED if hungry < 2 transition to HAPPY BORED If bored >= 4…
Write an if-statement that will compare the value in price against the value in budget. If price is greater than budget, then print the message “Too expensive”; otherwise print the message “Just right”.
For what values of x is the following if statement true? int y = 10; int x; if (( x / y == 1) && ( x % 2 == 1 )){ doSomething(); }

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