A study was undertaken to investigate the effectiveness of an aquarobic exercise program for patients with osteoarthritis. A convenience sample of 70 individuals with arthritis was selected, and each person was randomly assigned to one of two groups. The first group participated in a weekly aquarobic exercise program for 8 weeks; the second group served as a control. Several pieces of data were collected from the individuals, including their total cholesterol (mg).  Determine if there is a significant difference in the mean cholesterol for the two groups (aquarobic & control) at the start of the study using a significance level of 0.01.    Difference Sample Diff. Std. Error df Aquarobic - Control -13.9045 6.8214 67.8635 What hypotheses should be tested? Make sure to select the hypotheses which are written with notation consistent with the type of samples selected. Ho:μd=0Ho:μd=0 Ha:μd>0Ha:μd>0 Ho:μd=0Ho:μd=0 Ha:μd<0Ha:μd<0 Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1<μ2Ha:μ1<μ2 Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1>μ2Ha:μ1>μ2 Ho:μ1=μ2Ho:μ1=μ2 Ha:μ1≠μ2Ha:μ1≠μ2 Ho:μd=0Ho:μd=0 Ha:μd≠0Ha:μd≠0 αα  =  TS: t =   (round to 3 decimal places) probability =      decision:     What conclusion is reached based upon the decision made in your test? At the 0.01 level, there is sufficient evidence to conclude there is a difference in the mean cholesterol of individuals participating in the aquarobic program and those in the control group. At the 0.01 level, there is not sufficient evidence to conclude there is a difference in the mean cholesterol of individuals participating in the aquarobic program and those in the control group. After the 8-week program, those who participated in the aquarobic program had their ending cholesterol measured, and the change in cholesterol was recorded for each participant. Estimate the mean cholesterol change using 99% confidence.   The formula which should be used for this interval is: (¯y1−¯y2)±t√s21n1+s22n2(y¯1-y¯2)±ts12n1+s22n2 ¯yd±tsd√ndy¯d±tsdnd With % confidence, we estimate that the mean cholesterol before participating in 8 weeks of aquarobics is between mg and mg  than the mean cholesterol after participation. Note: Round the limits of your interval to three decimal places. In the last box type the appropriate word - more or less. Think carefully about what positive and negative differences mean about the change in cholesterol based on how the differences were taken.  Difference Sample Diff. Std. Error Critical Pt  Pre - Post  18.6752 0.8614  2.7284  A 99% confidence interval was also calculated for the change in total cholesterol (pre - post) for the control group. That interval was found to be (-3.053, 4.538). Based on this interval and the one which you calculated for the aquarobic group, what conclusion would you draw? Neither group had a significant change in mean cholesterol. The mean cholesterol for the control group increased, while the aquarobic group had a significant decrease in mean cholesterol. Both groups had a significant decrease in mean cholesterol. However, the decrease for the aquarobic group was larger. The aquarobic group did not have a significant change in mean cholesterol, while the control group had a significant increase in mean cholesterol. The control group did not have a significant change in mean cholesterol, while the aquarobic group had a significant decrease in mean cholesterol.

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
icon
Related questions
Question

A study was undertaken to investigate the effectiveness of an aquarobic exercise program for patients with osteoarthritis. A convenience sample of 70 individuals with arthritis was selected, and each person was randomly assigned to one of two groups. The first group participated in a weekly aquarobic exercise program for 8 weeks; the second group served as a control. Several pieces of data were collected from the individuals, including their total cholesterol (mg). 

Determine if there is a significant difference in the mean cholesterol for the two groups (aquarobic & control) at the start of the study using a significance level of 0.01.   

Difference Sample Diff. Std. Error df
Aquarobic - Control -13.9045 6.8214 67.8635
  • What hypotheses should be tested? Make sure to select the hypotheses which are written with notation consistent with the type of samples selected.
    Ho:μd=0Ho:μd=0
    Ha:μd>0Ha:μd>0
    Ho:μd=0Ho:μd=0
    Ha:μd<0Ha:μd<0
    Ho:μ1=μ2Ho:μ1=μ2
    Ha:μ1<μ2Ha:μ1<μ2
    Ho:μ1=μ2Ho:μ1=μ2
    Ha:μ1>μ2Ha:μ1>μ2
    Ho:μ1=μ2Ho:μ1=μ2
    Ha:μ1≠μ2Ha:μ1≠μ2
    Ho:μd=0Ho:μd=0
    Ha:μd≠0Ha:μd≠0
  • αα  = 
  • TS: t =   (round to 3 decimal places)
  • probability =     
  • decision:    
  • What conclusion is reached based upon the decision made in your test?
    • At the 0.01 level, there is sufficient evidence to conclude there is a difference in the mean cholesterol of individuals participating in the aquarobic program and those in the control group.
    • At the 0.01 level, there is not sufficient evidence to conclude there is a difference in the mean cholesterol of individuals participating in the aquarobic program and those in the control group.

After the 8-week program, those who participated in the aquarobic program had their ending cholesterol measured, and the change in cholesterol was recorded for each participant. Estimate the mean cholesterol change using 99% confidence.  

  • The formula which should be used for this interval is:
    • (¯y1−¯y2)±t√s21n1+s22n2(y¯1-y¯2)±ts12n1+s22n2
    • ¯yd±tsd√ndy¯d±tsdnd
  • With % confidence, we estimate that the mean cholesterol before participating in 8 weeks of aquarobics is between mg and mg  than the mean cholesterol after participation. Note: Round the limits of your interval to three decimal places. In the last box type the appropriate word - more or less. Think carefully about what positive and negative differences mean about the change in cholesterol based on how the differences were taken. 
Difference Sample Diff. Std. Error Critical Pt
 Pre - Post  18.6752 0.8614  2.7284 

A 99% confidence interval was also calculated for the change in total cholesterol (pre - post) for the control group. That interval was found to be (-3.053, 4.538). Based on this interval and the one which you calculated for the aquarobic group, what conclusion would you draw?

  • Neither group had a significant change in mean cholesterol.
  • The mean cholesterol for the control group increased, while the aquarobic group had a significant decrease in mean cholesterol.
  • Both groups had a significant decrease in mean cholesterol. However, the decrease for the aquarobic group was larger.
  • The aquarobic group did not have a significant change in mean cholesterol, while the control group had a significant increase in mean cholesterol.
  • The control group did not have a significant change in mean cholesterol, while the aquarobic group had a significant decrease in mean cholesterol.

 

 

 
 
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps with 2 images

Blurred answer
Similar questions
Recommended textbooks for you
Holt Mcdougal Larson Pre-algebra: Student Edition…
Holt Mcdougal Larson Pre-algebra: Student Edition…
Algebra
ISBN:
9780547587776
Author:
HOLT MCDOUGAL
Publisher:
HOLT MCDOUGAL
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Big Ideas Math A Bridge To Success Algebra 1: Stu…
Algebra
ISBN:
9781680331141
Author:
HOUGHTON MIFFLIN HARCOURT
Publisher:
Houghton Mifflin Harcourt
Glencoe Algebra 1, Student Edition, 9780079039897…
Glencoe Algebra 1, Student Edition, 9780079039897…
Algebra
ISBN:
9780079039897
Author:
Carter
Publisher:
McGraw Hill
College Algebra (MindTap Course List)
College Algebra (MindTap Course List)
Algebra
ISBN:
9781305652231
Author:
R. David Gustafson, Jeff Hughes
Publisher:
Cengage Learning
College Algebra
College Algebra
Algebra
ISBN:
9781938168383
Author:
Jay Abramson
Publisher:
OpenStax