Acetyisalicylic acid commonly knowWn as Aspirin is used tó treat feve inflammation, and acts as a blood thinning agent. A group of STEM student experimented on the synthesis of this compound using recrystallizatio technique. The following are the initial materials for the experiment: 5.00 g c pure salicylic acid, 7.14 g of acetic anhydride and 8 drops concentrate sulfuric acid as catalyst. After successful synthesis, the group was able to collec 5.25 grams of Aspirin. (Atomic weights: Ċ= 12 amu; H = i amu; O= 16 amu density acetic anhydride = 1.08 g/mL) Chemical reaction involved: он E-CH, с-он C-CH CH3-C-OH -O- Acetic anhydride Acetic Acid Salicylic acid (C7H&O3) Acetylsaicyic acid (C 9H3O4) (C 4H6O3) (C 2 H402) ow many molecules will be present in the Aspirin produced? O 2.18 x1022 7.44 x1022 8.13 x1022 O 9.20 x1022 None of the above

Acetyisalicylic acid commonly knowWn as Aspirin is used tó treat feve inflammation, and acts as a blood thinning agent. A group of STEM student experimented on the synthesis of this compound using recrystallizatio technique. The following are the initial materials for the experiment: 5.00 g c pure salicylic acid, 7.14 g of acetic anhydride and 8 drops concentrate sulfuric acid as catalyst. After successful synthesis, the group was able to collec 5.25 grams of Aspirin. (Atomic weights: Ċ= 12 amu; H = i amu; O= 16 amu density acetic anhydride = 1.08 g/mL) Chemical reaction involved: он E-CH, с-он C-CH CH3-C-OH -O- Acetic anhydride Acetic Acid Salicylic acid (C7H&O3) Acetylsaicyic acid (C 9H3O4) (C 4H6O3) (C 2 H402) ow many molecules will be present in the Aspirin produced? O 2.18 x1022 7.44 x1022 8.13 x1022 O 9.20 x1022 None of the above

Organic Chemistry

8th Edition

ISBN:9781305580350

Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Publisher:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote

Chapter5: Alkenes: Bonding, Nomenclature, And Properties

Section: Chapter Questions

Problem 5.31P

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Given the balanced reaction between salicylic acid (C7H6O3) and acetic anhydride (C4H6O3) to produce ASA or acetylsalicylic acid (C9H8O4) and acetic acid (C2H4O2), the following experimental materials are provided: 5.00 g of pure salicylic acid, 7.14 g of acetic anhydride and 8 drops concentrated sulfuric acid as catalyst. After successful synthesis, the group was able to collect 5.25 grams of acetylsalicylic acid. (Atomic weights: C= 12 amu; H = 1 amu; O= 16 amu; density acetic anhydride = 1.08 g/mL). What is the THEORETICAL yield of ASA in the experiment?
Given the balanced reaction between salicylic acid (C7H6O3) and acetic anhydride (C4H6O3) to produce ASA or acetylsalicylic acid (C9H8O4) and acetic acid (C2H4O2), the following experimental materials are provided: 5.00 g of pure salicylic acid, 7.14 g of acetic anhydride and 8 drops concentrated sulfuric acid as catalyst. After successful synthesis, the group was able to collect 5.25 grams of acetylsalicylic acid. (Atomic weights: C= 12 amu; H = 1 amu; O= 16 amu; density acetic anhydride = 1.08 g/mL). What is the PERCENTAGE in the experiment?
Given the balanced reaction between salicylic acid (C7H6O3) and acetic anhydride (C4H6O3) to produce ASA or acetylsalicylic acid (C9H8O4) and acetic acid (C2H4O2), the following experimental materials are provided: 5.00 g of pure salicylic acid, 7.14 g of acetic anhydride and 8 drops concentrated sulfuric acid as catalyst. After successful synthesis, the group was able to collect 5.25 grams of acetylsalicylic acid. (Atomic weight: C = 12 amu; H = 1 amu; O = 16 amu; density acetic anhydride = 1.08 g/mL). a. How much of the EXCESS reagent is left unused after the reaction? b. What is the PERCENTAGE in the experiment? c. What is the THEORETICAL yield of ASA in the experiment?
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A 0.9134-g of KIO3 is dissolved in 500-mL distilled water. A 50.0-mL aliquot portion was run down into an Erlenmeyer flask and 2-g of KI and 2-mL of 6M HCl were added to it. Directly after, the solution was titrated with a 24.47-mL Na2S2O3 solution to a faint yellow solution. Starch TS was added to the resulting solution and the titration with the Na2S2O3 solution continued wherein an additional 1.33-mL was required to bring the blue color of the solution to disappear completely. MW: KIO3 = 214.0 g/mol ; Na2S2O3 = 158.1 g/mol Compute the M of the Na2S2O3 solution. 0.1047 M None of the choices 0.1107 M 0.09926 M