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ARTING AMOUNT X How many moles of CH₁2 (cyclohexane) must be reacted according to the following balanced chemical reaction to transfer -419.1 kJ of heat? ADD FACTOR g CO₂ X -46.57 C6H₁2()+ 9 O₂(g) 6 CO₂(g) + 6 H₂O(g) ΔΗ = -3919.4 kJ 1.164 x 106 32.00 mol CO₂ 9.351 0.1069 g 0₂ 6 -419.1 kJ g C6H₁2 ANSWER 6.022 x 1023 84.16 g H₂O mol C6H₁2 9 RESET mol O₂ 5 6.439 x 1022 -3919.4 mol H₂O 1 J

ARTING AMOUNT X How many moles of CH₁2 (cyclohexane) must be reacted according to the following balanced chemical reaction to transfer -419.1 kJ of heat? ADD FACTOR g CO₂ X -46.57 C6H₁2()+ 9 O₂(g) 6 CO₂(g) + 6 H₂O(g) ΔΗ = -3919.4 kJ 1.164 x 106 32.00 mol CO₂ 9.351 0.1069 g 0₂ 6 -419.1 kJ g C6H₁2 ANSWER 6.022 x 1023 84.16 g H₂O mol C6H₁2 9 RESET mol O₂ 5 6.439 x 1022 -3919.4 mol H₂O 1 J

Chemistry by OpenStax (2015-05-04)
Chemistry by OpenStax (2015-05-04)
1st Edition
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Chapter5: Thermochemistry
Section: Chapter Questions
Problem 47E: How many moles of isooctane must be burned to produce loo U of heat under standard state conditions?
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pic: Updated Schedule C app.101edu.co STARTING AMOUNT X 08 X Aktiv Chemistry X + How many moles of C6H₁2 (cyclohexane) must be reacted according to the following balanced chemical reaction to transfer -419.1 kJ of heat? ADD FACTOR g CO₂ x( ) -46.57 C6H12()+9 1.164 x 106 32.00 9 mol CO₂ 9.351 0.1069 Question 5 of 11 g 0₂ O₂(g) → 6 CO₂(g) + 6H₂O(g) ΔΗ = -3919.4 kJ 6 -419.1 kJ g C6H₁2 ANSWER 6.022 x 1023 84.16 g H₂O mol C6H₁2 9 RESET mol O₂ 5 6.439 x 1022 -3919.4 mol H₂O 1 J Ma
Transcribed Image Text:pic: Updated Schedule C app.101edu.co STARTING AMOUNT X 08 X Aktiv Chemistry X + How many moles of C6H₁2 (cyclohexane) must be reacted according to the following balanced chemical reaction to transfer -419.1 kJ of heat? ADD FACTOR g CO₂ x( ) -46.57 C6H12()+9 1.164 x 106 32.00 9 mol CO₂ 9.351 0.1069 Question 5 of 11 g 0₂ O₂(g) → 6 CO₂(g) + 6H₂O(g) ΔΗ = -3919.4 kJ 6 -419.1 kJ g C6H₁2 ANSWER 6.022 x 1023 84.16 g H₂O mol C6H₁2 9 RESET mol O₂ 5 6.439 x 1022 -3919.4 mol H₂O 1 J Ma
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