ATP Synthase is known to catalyze the synthesis of ATP with a ΔG°’ close to zero, and a Keq' close to. Why is the value of ΔG°’ different from the known value which is 30.5 kJ/mol (the energy for the reverse of ATP hydrolysis)? If the Keq' value is close to one, how is it ensured that the reaction is driven to the product side and more ATP is obtained?
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ATP Synthase is known to catalyze the synthesis of ATP with a ΔG°’ close to zero, and a Keq' close to. Why is the value of ΔG°’ different from the known value which is 30.5 kJ/mol (the energy for the reverse of ATP hydrolysis)?
If the Keq' value is close to one, how is it ensured that the reaction is driven to the product side and more ATP is obtained?
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- ATP Synthase is known to catalyze the synthesis of ATP with a ΔG°’ close to zero, and a Keq' close to 1. Why is the value of ΔG°’ different from the known value which is 30.5 kJ/mol (the energy for the reverse of ATP hydrolysis)? If the Keq' value is close to one, how is it ensured that the reaction is driven to the product side and more ATP is obtained?If a reaction has a ΔG°′ value of at least −30.5 kJ · mol−1, suffi -cient to drive the synthesis of ATP (ΔG°′ = 30.5 kJ · mol−1), can it still drive the synthesis of ATP in vivo when its ΔG is only −10 kJ · mol−1? Explain.The hydrolysis of ATP has an enthalpy and entropy of -24.3 kJ/mol and +21.6 J.K-1.mol-1, respectively, at 37 o C. What is the free energy change for the hydrolysis of 5 mols of ATP? Explain what contributes to the negative enthalpy change and positive entropy change in this reaction. What physical characteristics of the reaction would change if an ATP hydrolase enzyme is added to the solution?
- The standard free energy variation of the ATP hydrolysis reaction is ΔGº’ = -30.5 kJ / mol ATP + H2O ⇄ ADP + Pi In red blood cells, when the concentration of Pi is 1.6 mM, the real change in energy free is ΔG = - 50'2 kJ / mol. a) Calculate under these conditions what is the ratio [ATP] / [ADP] in the red blood cells. b) Determine the equilibrium constant K 'of the reaction outlined above. c) If the ADP concentration were 0.2mM, what would be the effective concentration of ATP corresponding to equilibrium.If a 0.1 M solution of glucose 1- phosphate at 25 °C is incubated with a catalytic amount of phosphoglucomutase, the glucose 1-phosphate is transformed to glucose 6-phosphate. At equilibrium, the concentrations of the reaction components are Calculate Keq and ΔG′° for this reaction.Based on the definition of kcat, substitute a value that can be measured and yet still represents the value associated with the original concentration of the R. What would the rate or velocity of the reaction be equal to under these circumstances? How can cells increase Vmax? What variable that we could change would directly impact Vmax? Would the value of KM be affected by the ways you determined that Vma,x could be increased? What does this indicate about KM? Thinking about how catalysts work, about the Michaelis-Menten Equation, and the definition of kcat, what specifically does the enzyme change in the reaction mechanism to increase the rate? If an enzyme follows the 2 step mechanism proposed by Michaelis-Menten, what do you know about this enzyme? Be very specific and comprehensive. Please answer very soon will give rating surely
- At what substrate concentration would an enzyme with a kcat of 25.0 s-1 and a KM of 3.5 mM operate at 25% of its maximal rate? How many reactions would the enzyme catalyze in 45 seconds when it is fully saturated with substate, assuming the enzyme has one active site?When enzyme solutions are heated, there is a progressive loss of catalytic activity over time due to denaturation of the enzyme. A solution of the enzyme hexokinase incubated at 45 °C lost 50% of its activity in 12 min, but when incubated at 45 °C in the presence of a very large concentration of one of its substrates, it lost only 3% of its activity in 12 min. Suggest why thermal denaturation of hexokinase was retarded in the presence of one of its substrates.If the Go for ATP hydrolysis into ADP + inorganic phosphate is 7.3 kcal/mole, and the Go for glutamine synthesis from glutamic acid and NH3 is +3.4 kcal/mole, calculate the average Go for coupling these two reactions (glutamic acid + NH3 + ATP glutamine + ADP + inorganic phosphate
- Calculate the standard free-energy change of the reaction catalyzed by theenzyme phosphoglucomutase, given that, starting with 20 mM glucose 1-phosphate and no glucose 6- phosphate, the final equilibrium mixture at 25 °C and pH 7.0 contains 1.0 mM glucose 1-phosphate and 19 mM glucose 6-phosphate. Does the reaction in the direction of glucose 6-phosphate formation proceed with a loss or a gain of free energy?The standard reduction potential for ubiquione (A or coenzyme Q) is .045 V, and the standard reduciton potential (E) for FAD is -0.219 V. Using these values, show that the oxidation for FADH2 by ubiquinone theoretically liberates enough energy to drive the synthesis of ATP. Faraday constant =96.48KJ/Vol delta G' standard for ATP Synthesis is +30.5 KJ/mol R=8.314 J/mol K=1.987 cal/mol KGiven that the standard free-energy change for the reaction glucose + Pi →glucose 6-phosphate is 13.8 kJ/mol, and the standard free-energy change forthe reaction ATP → ADP + Pi is −30.5 kJ/mol, what is the free-energychange for the reaction glucose + ATP → glucose 6-phosphate + ADP?