QUESTION 17 calculate the KM AND the total amount of enzyme present in these experiments. The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2: Watch your exponents.) Kcat= Substrate concentration (mm) 1 2 4 6 100 1,000 The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, 250 334 376 500 500 Vmax [Et] Initial velocity (μmol/min) 167 G. 10 mM H. 250 uM 1. 2 mM J. 100 mM Part 1 Total Enzyme amount (choose from options A-E) Part 2 ( Enzyme KM: (choose from options G-J) A. Total enzyme = 10 umol B. Total enzyme = 0.1 umol OC. Total enzyme = 100 μmol D. Total enzyme = 1000 μmol E. Total enzyme = 10 μmol OF Vo = Vmax[S] KM + [S]

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Chapter1: Biochemistry: An Evolving Science
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QUESTION 17
calculate the KM AND
the total amount of enzyme present in these experiments.
The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2:
Watch your exponents.)
Kcat=
Substrate
concentration
(mm)
1
2
4
6
100
1,000
The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data,
250
334
376
500
500
Vmax
[Et]
Initial
velocity
(μmol/min)
167
G. 10 mM
H. 250 uM
1. 2 mM
J. 100 mM
Part 1
Total Enzyme amount (choose from options A-E)
Part 2 (
Enzyme KM: (choose from options G-J)
A. Total enzyme = 10 umol
B. Total enzyme = 0.1 umol
OC. Total enzyme = 100 μmol
D. Total enzyme = 1000 μmol
E. Total enzyme = 10 μmol
OF
Vo =
Vmax[S]
KM + [S]
Transcribed Image Text:QUESTION 17 calculate the KM AND the total amount of enzyme present in these experiments. The following equations relate to this question. (Hint 1: some data is directly apparent without need to do calculations; Hint 2: Watch your exponents.) Kcat= Substrate concentration (mm) 1 2 4 6 100 1,000 The turnover number for an enzyme is known to be 5,000 min-1. From the following set of data, 250 334 376 500 500 Vmax [Et] Initial velocity (μmol/min) 167 G. 10 mM H. 250 uM 1. 2 mM J. 100 mM Part 1 Total Enzyme amount (choose from options A-E) Part 2 ( Enzyme KM: (choose from options G-J) A. Total enzyme = 10 umol B. Total enzyme = 0.1 umol OC. Total enzyme = 100 μmol D. Total enzyme = 1000 μmol E. Total enzyme = 10 μmol OF Vo = Vmax[S] KM + [S]
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