Compute: z =√x-y Ex: If the input is 4.0 3.0, then the output is: 1.0 #include > #include < #include using namespace std; int main() { double x; double y; double z; } cin >> X; cin >> y; /* Your code goes here */ cout << fixed <

I need the pseudocode or flowchart for the following code:    #include <stdio.h>#include <stdlib.h>#include <string.h>#define array_Length 5#define BUFSIZE 40//Calculate the average int getmean (int *arr, int length) {int sum = 0;for (int i=0; i<length; i++){sum += arr[i];}//end for loopreturn sum/length;}//Output the Maximum int find_Maximum(int *arr,int length) {int max=0;for(int i=1;i<length;++i)if (arr[i]>arr[max])max=i;return arr[max];}//end for loopint main() {//Intialize and Declare Variables int values[array_Length] = {0};char buffer[BUFSIZE];int index = 0;int x = 0;while(x<5) {//Ask user to input integer printf ("Type a number:");x++;if (fgets(buffer, BUFSIZE, stdin) == NULL)break;//Save new int in the array values[index] = atoi(buffer);//Move the index to the next element, wrap around if needed index = (index + 1) % array_Length;//Display the array, maximum number and the average of its valueprintf("[");for (int i= 0; i < array_Length; i++)…

#include <bits/stdc++.h>using namespace std;int main() { double matrix[4][3]={{2.5,3.2,6.0},{5.5, 7.5, 12.6},{11.25, 16.85, 13.45},{8.75, 35.65, 19.45}}; cout<<"Input no in first row of matrix"<<endl; for(int i=0;i<3;i++){     double t;     cin>>t;     matrix[0][i]=t; } cout<<"Contents of the last column in matrix"<<endl; for(int i=0;i<4;i++){     cout<<matrix[i][2]<<" "; } cout<<"Content of first row and last column element in matrix is: "<<matrix[0][3]<<endl; matrix[3][2]=13.6; cout<<"Updated matrix is :"<<endl; for(int i=0;i<4;i++){     for(int j=0;j<3;j++){         cout<<matrix[i][j]<<" ";     }cout<<endl; } return 0;}   Please explain this code

using c++ complete the code where it says  , /* Your code goes here */ compute z= y- √2   #include <iostream>#include <cmath>#include <ios>#include <iomanip>using namespace std; int main() {double x;double y;double z; cin >> x;cin >> y; /* Your code goes here */ cout << fixed << setprecision(2); // This will output only 2 decimal places.cout << z << endl; return 0;}