Consider a two-period dynamic resource allocation problem where the efficient resource allocation implies a market price of $6 in the first period (i.e., P1 = 6). Assuming that the constant marginal extraction cost in both periods is $3 and that the social discount rate is 10% (i.e., r = 0.10), the socially efficient undiscounted market price in the second period (P2) must be (Hint: use the efficiency condition.) Question 10Answer a. $7 b. $6.30 c. $600 d. $6

Please label the graph point where the socially optimal equilibrium is

You manage two chocolate factories. Using only these two factories, you must produce exactly 420 kgs of chocolate daily at lowest possible cost. Mathematically, you have: Q1 = Quantity produced at Chocolate Factory #1 Q2 = Quantity produced at Chocolate Factory #2 Daily total overall production: Q1 – Q2 = 420 At present, each factory produces half the overall requirement. This means that Q1 = 210, Q2 = 210   a)  Following your logic , you realize that as long as the marginal cost is different between the two factories, you can lower overall cost while maintaining production at 420 kgs. So, to reduce the overall cost to the lowest possible, you decide to move more than 1 kilogram from one factory to another. As a result, each factory will produce a different quantity of chocolate while the overall daily production remains at 420 kgs. To minimize overall cost, how many kilograms will you order/instruct Factory #1 to produce? Q1 = ____________kgs And how many kilograms would you…

The biological relationship between the growth for the fish population and the size of the fish population is g = 12S(1 - S/4) where g is the growth of the fish population and S is the size of the population. The size of the harvest is a function of the amount of human effort expended b = 3ES where E is the level of effort. Market price of fish per unit is $100 and a constant marginal cost of effort is $40. We can derive the free-access equilibrium effort level Ef by setting the net benefits function equal to zero. Then, E f = in one decimal place. Hint: Write the number

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