Figure and table given  below shows the design details of a taper turning operation with a cutting speed of 22 m/ minute, feed 0.2 mm/ revolution; Depth of cut of 0.5 mm.   Using the given data find the following.  (a) Diameter "D" in mm . (b)  Spindle speed in rpm. (c) Time for n passes  to complete taper turning in minutes.

Precision Machining Technology (MindTap Course List)
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ISBN:9781285444543
Author:Peter J. Hoffman, Eric S. Hopewell, Brian Janes
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Chapter4: Drill Press
Section4.3: Drill Press Operations
Problem 3RQ: What unit of measure is used to define cutting speeds?
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Figure and table given  below shows the design details of a taper turning operation with a cutting speed of 22 m/ minute, feed 0.2 mm/ revolution; Depth of cut of 0.5 mm.   Using the given data find the following.  (a) Diameter "D" in mm . (b)  Spindle speed in rpm. (c) Time for n passes  to complete taper turning in minutes.
d
q°
L1
SI.
Parameter in
Dimension in
No: Drawing
mm
1
d
35
2
L1
28
|Cutting speed (Cs) in m/
minute
3
22
Taper angle "a" in degrees
4
14
Transcribed Image Text:d q° L1 SI. Parameter in Dimension in No: Drawing mm 1 d 35 2 L1 28 |Cutting speed (Cs) in m/ minute 3 22 Taper angle "a" in degrees 4 14
Expert Solution
Step 1

Given dataCutting speed Vc = 22m/minFeed f = 0.2mm/revolutionDepth of cut d = 0.5mmTaper angle α = 40Small diameter d = 35mmLength of cut L1 = 28mmTo determine 1 ] Diameter D = ? (mm)2] Spindle speed N = ?(rpm)3] Time for n passes to complete taper turning.

Mechanical Engineering homework question answer, step 1, image 1

Step 2

Calculation diameter of the shaft with the help of taper anlge tan(α2) = D-d2LD-d = tan(α2) ×2LD = tan(α2) ×2L+dD = tan(42) ×2(28)+35D = tan(2) ×(56)+35D = 36.9555mm = 37mm(Approx)

Step 3

Calculation of spindle speed N(rpm)Cutting velocity Vc = πDN1000Spindle speed N = Vc×1000 πDD = 37mmVc = 22m/min N = Vc×1000 πD N = 22×1000 π×37N = 189.26  (rpm)

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