Figure out the mRNA and amino acid sequences each mutant gene would code for and compare them to the original protein

Concepts of Biology
1st Edition
ISBN:9781938168116
Author:Samantha Fowler, Rebecca Roush, James Wise
Publisher:Samantha Fowler, Rebecca Roush, James Wise
Chapter9: Molecular Biology
Section: Chapter Questions
Problem 6RQ: A promoter is ______. a. a specific sequence of DNA nucleotides b. a specific sequence of RNA...
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Figure out the mRNA and amino acid sequences each mutant gene would code for and compare them to the original protein

Expert Solution
Step 1

DNA is a double-stranded structure and has genes in a form of coded sequence. The template strand of the gene transcribes itself into a complementary mRNA strand. the mRNA sequence is used for the translation of the genetic information into a polypeptide chain. The mRNA sequence is read in the form of triplets known as codons. Each codon codes for one of the twenty amino acids.

Step 2

Mutation#4

Deletion- Frameshift mutation

In this type of mutation, one or more nucleotides are lost or deleted from the DNA segment resulting in the shifting of the reading frame of the base sequences. Due to deletion, the reading frame shifts in the backward direction.

 

template strand

coding strand

mRNA

Amino acid sequence

1

T

A

A

Methionine or start codon

2

A

T

U

3

C

G

G

4

A

T

U

Cysteine

5

C

G

G

6

A

T

U

7

A

T

U

Tyrosine

8

T

A

A

9

G

C

C

10

A

T

U

Stop codon

15

T

A

A

16

C

G

G

17

T

A

A

Stop codon codes for the termination of the polypeptide chain synthesis. Hence, no further translation will take place in this case of a frameshift mutation.

18

G

C

C

19

A

T

U

20

C

G

G

21

G

C

C

22

G

C

C

23

G

C

C

24

G

C

C

25

T

A

A

26

C

G

G

27

C

G

G

28

C

G

G

29

C

G

G

30

C

G

G

31

A

T

U

32

T

A

A

33

T

A

A

 

The amino acid sequence for the given strand with frameshift mutation will be met-cys-tyr-stop.

Step 3

Mutation#5

Insertion- Frameshift mutation

In this type of mutation, one or more nucleotides are added in the DNA segment resulting in the shifting of the reading frame of the base sequences. Due to insertion, the reading frame shifts in the forward direction.

 

template strand

coding strand

mRNA

Amino acid sequence

1

T

A

A

Methionine or start codon

2

A

T

U

3

C

G

G

4

A

T

U

Cysteine

5

C

G

G

6

A

T

U

7

A

T

U

Tyrosine

8

T

A

A

9

G

C

C

10

A

T

U

Phenylalanine

11

A

T

U

12

A

T

U

13

C

G

G

Glutamic acid

14

T

A

A

15

T

A

A

16

C

G

G

Aspartic acid

17

T

A

A

18

G

C

C

19

A

T

U

Cysteine

20

C

G

G

 

G

C

C

 

A

T

U

Serine

21

G

C

C

22

G

C

C

23

G

C

C

Proline

24

G

C

C

25

T

A

A

26

C

G

G

Glycine

27

C

G

G

28

C

G

G

29

C

G

G

Glycine

30

C

G

G

31

A

T

U

32

T

A

A

 

33

T

A

A

 

Amino acid sequence of the DNA strand with insertion-frameshift mutation: met-cys-tyr-phe-glu-asp-cys-ser-pro-gly-gly-

There is no stop codon and the the last two neucleotides are also not in the form of triplets.

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