Given string stringVal on one line, integer idxBegin on a second line, and integer desiredLen on a third line, output the substring of stringVal starting at position idxBegin and with length desiredLen. End with a newline. Ex: If the input is: Fuzzy bear 3 4 then the output is: zy b Note: Using a pre-defined string function, the solution can be just one line of code. #include #include using namespace std; int main() {    string stringVal;    int idxBegin;    int desiredLen;    getline(cin, stringVal);    cin >> idxBegin;    cin >> desiredLen;    /* Your code goes here */    return 0; }

Given string stringValue on one line, string addStr on a second line, and string partialString on a third line, insert the contents of addStr in stringValue right before the first occurrence of partialString. Ex: If the input is: FuzzyBear Wuzzy Be then the output is: FuzzyWuzzyBear #include <iostream>#include <string>using namespace std; int main() {   string stringValue;   string addStr;   string partialString;    getline(cin, stringValue);   getline(cin, addStr);   getline(cin, partialString);    /* Your code goes here */      cout << stringValue << endl;      return 0;}

What characters are utilised as delimiters when you supply null as a parameter to the Split method of a string object?

The countSubstring function will take two strings as parameters and will return an integer that is the count of how many times the substring (the second parameter) appears in the first string without overlapping with itself. This method will be case insensitive.   For example: countSubstring(“catwoman loves cats”, “cat”) would return 2 countSubstring(“aaa nice”, “aa”) would return 1 because “aa” only appears once without overlapping itself.     public static int countSubstring(String s, String x) { if (s.length() == 0 || x.length() == 0) return 1;   if (s.length() == 1 || x.length() == 1){ if (s.substring(0,1).equals(x.substring(0,1))){ s.replaceFirst((x), " "); return 1 + countSubstring(s.substring(1), x); } else { return 0 + countSubstring(s.substring(1), x); } } return countSubstring(s.substring(0,1), x) + countSubstring(s.substring(1), x); }   public class Main { public static void main(String[] args) { System.out.println(Recursion.countSubstring("catwoman loves cats","cat"));…