II Review | Constants MISSED THIS? Read Section 16.6 (Pages 696 - 699) ; Watch IWE 16.5 . Part A Consider the following reaction: Fe3+ (aq) + SCN (aq) A solution is made containing an initial Fe+] of 1.2x10-3 M and an initial [SCN-] of 8.1×10-4 M . At equilibrium, [FESCN²+] = 1.8×10-4 M. FESCN2+ (aq) Calculate the value of the equilibrium constant (K.). Express your answer using two significant figures. • View Available Hint(s) ν ΑΣΦ Ke =

Chemistry
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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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A openvellum.ecollege.com/course.html?courseld=16196689&HepID=aeb74d6324e98a415a0c4c5c32b9c2e6#10001
I Review | Constants | Periodic Table
MISSED THIS? Read Section
16.6 (Pages 696 - 699) ; Watch IWE 16.5 .
Part A
Consider the following reaction:
Fe3+
(aq) + SCN (aq) = FESCN²+ (aq)
A solution is made containing an initial Fe+ of
1.2x10-3 M and an initial [SCN ] of 8.1×10-4 M
. At equilibrium, [FESCN²+] = 1.8×10-4 M .
Calculate the value of the equilibrium constant (Kc).
Express your answer using two significant figures.
View Available Hint(s)
Πνα ΑΣφ
?
K =
Submit
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Transcribed Image Text:2.2.1 Gene T x m Inbox (9,414 × M Verify your e X My Question x Things I Can x Course Hom x + USC A openvellum.ecollege.com/course.html?courseld=16196689&HepID=aeb74d6324e98a415a0c4c5c32b9c2e6#10001 I Review | Constants | Periodic Table MISSED THIS? Read Section 16.6 (Pages 696 - 699) ; Watch IWE 16.5 . Part A Consider the following reaction: Fe3+ (aq) + SCN (aq) = FESCN²+ (aq) A solution is made containing an initial Fe+ of 1.2x10-3 M and an initial [SCN ] of 8.1×10-4 M . At equilibrium, [FESCN²+] = 1.8×10-4 M . Calculate the value of the equilibrium constant (Kc). Express your answer using two significant figures. View Available Hint(s) Πνα ΑΣφ ? K = Submit Previous Answers Request Answer * Incorrect; Try Again; 2 attempts remaining Provide Feedback Next :
2.2.1 Gene T x
Inbox (9,414 × M Verify your e X
My Question x
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<Chapter 16 HW #3
Item 11
11 of 17
I Review | Constants | Periodic Table
MISSED THIS? Read Section
16.8 (Pages 701 - 710) ; Watch KCV 16.8, IWE
16.9 .
Part A
a reaction vessel initially contains an N2O4 concentration of 0.0500 M at 500
K, what are the equilibrium concentrations of N2O4 and NO2 at 500 K?
For the reaction
N2O4(g) = 2NO2 (g)
Express your answers in moles per liter to three significant figures
separated by a comma.
Ke
= 0.513 at 500 K.
• View Available Hint(s)
ΑΣΦ
?
[N2O4], [NO2] =
M
Submit
Previous Answers Request Answer
X Incorrect; Try Again; 3 attempts remaining
Provide Feedback
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Transcribed Image Text:2.2.1 Gene T x Inbox (9,414 × M Verify your e X My Question x Things I Can X Course Hom x + USC -> A openvellum.ecollege.com/course.html?courseld=16196689&HepID=aeb74d6324e98a415a0c4c5c32b9c2e6#10001 <Chapter 16 HW #3 Item 11 11 of 17 I Review | Constants | Periodic Table MISSED THIS? Read Section 16.8 (Pages 701 - 710) ; Watch KCV 16.8, IWE 16.9 . Part A a reaction vessel initially contains an N2O4 concentration of 0.0500 M at 500 K, what are the equilibrium concentrations of N2O4 and NO2 at 500 K? For the reaction N2O4(g) = 2NO2 (g) Express your answers in moles per liter to three significant figures separated by a comma. Ke = 0.513 at 500 K. • View Available Hint(s) ΑΣΦ ? [N2O4], [NO2] = M Submit Previous Answers Request Answer X Incorrect; Try Again; 3 attempts remaining Provide Feedback Next >
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