Implement, using only the Queue kernel methods, the static method declared as follows and answer the questions below: Reports the smallest integer in the given {@code Queue). @param q the queue of integer @return the smallest integer in the given queue @requires q /= empty_string @ensures min is in entries (q) and for all x: integer where (x is in entries (q)) (min <= x) ivate static int min (Queue q) {...} i. Why do you need the requires clause? ii. Why is the first line of the ensures clause important (min is in entries (q))? Explain what the implementation could do if this line was not included in the postcondition.

Can you write a program in python for the dining philosopher problems that do not have deadlock? You have to use semaphores and use the strategy that a philosopher only picks the fork if both (left and right) are available. def philosopher(id: int, fork: list): The main is if __name__ == "__main__": semaphoreList = list() #this list will hold one semaphore per fork Philosophers = 5 for i in range(Philosophers): semaphoreList.append(multiprocessing.Semaphore(1)) philosopherList = list() for i in range(Philosophers): #instantiate all processes representing philosophers philosopherList.append(multiprocessing.Process(target=philosopher, args=(i, semaphoreList))) for j in range(Philosophers): #start all child processes philosopherList[j].start() for k in range(Philosophers): #join all child processes philosopherList[k].join() sample output: DEBUG: philosopher2 has chopstick2 DEBUG: philosopher2 has chopstick3 DEBUG: philosopher2 eating DEBUG: philosopher1 has chopstick1 DEBUG: philosopher0…

Write a program that reads a line of text, changes each uppercase letter to lowercase, and places each letter both in a queue and onto a stack. The program should then verify whether the line of text is a palindrome (a set of letters or numbers that is the same whether read forward or backward). Cannot use <queue> Library, have to use queueADT class as shown in the below, "Queue Demo." Thank you, will up vote. #include <iostream> #include <cassert>using namespace std; template <class Type>class queueADT{public:    virtual bool isEmptyQueue() const = 0;    virtual bool isFullQueue() const = 0;    virtual void initializeQueue() = 0;    virtual Type front() const = 0; //Function to return the first element of the queue.    virtual Type back() const = 0; //Function to return the last element of the queue.    virtual void addQueue(const Type& queueElement) = 0; //Function to add queueElement to the queue.    virtual void deleteQueue() = 0; //Function to remove…

Using Queues Operation Enqueue,Dequeue, Write a algorithm of method names Contain_Equal that takes the strrings "aaabbb" in queue form as input and returns that the strings contain equal numbers of a's and b's A A A В В В Ouput Must be Like: Both A's and B's are Equal In Quantity Which Is 3.

Implement a circular queue by writing circular.h and circular.c. Here are the contents of circular.h: #define QUEUE_SIZE 100 typedef struct { int head; int tail; int itemCount; int items[QUEUE_SIZE]; } CircularQueue; void CircularInitialize(CircularQueue * q); void CircularEnqueue (CircularQueue * q, int value); int Circular Dequeue (CircularQueue * q, int *pValue); Using an array, implement a circular queue of up to 100 elements of type integer. Implement the functions CircularEnqueue() and Circular Dequeue () to place numbers in the head of the queue and read them from the tail of the queue tail. A circular queue only saves the last n entries (where n is the number of elements in the queue). Overwrite the oldest entries with newest entries once the queue is full.

USE PYTHON

def has_at_least(queue: Queue, n: int) -> bool:"""Return true iff queue contains at least n items. Precondition: n >= 0 >>> queue = Queue()>>> queue.enqueue(1)>>> queue.enqueue(2)>>> queue.enqueue(3)>>> has_at_least(queue, 3)True"""

Java

java Suppose queue is defined as LinkedQueue<Integer> queue = new LinkedQueue<>(); Show what is written by the following segment of code. SHOW YOUR WORK.

import java.util.*;import java.io.*; public class HuffmanCode {     private Queue<HuffmanNode> queue;        private HuffmanNode overallRoot;                 public HuffmanCode(int[] frequencies) {                queue = new PriorityQueue<HuffmanNode>();                                for (int i = 0; i < frequencies.length; i++) {                        if (frequencies[i] > 0) {                                HuffmanNode node = new HuffmanNode(frequencies[i]);                                node.ascii = i;                                queue.add(node);                        }                }                overallRoot = buildTree();              }                 public HuffmanCode(Scanner input) {                overallRoot = new HuffmanNode(-1);                while (input.hasNext()) {                        int asciiValue = Integer.parseInt(input.nextLine());                        String code = input.nextLine();                        overallRoot =…