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C. Purification of Water
1.For this part of the experiment, watch the video on the link(s) below:
a. Flocculation: https://www.youtube.com/watch?v=5uuQ77vAV_U&t=82s
Question:
Observation before flocculation. Observation after Flocculation
Step by step
Solved in 2 steps with 2 images
- Make a schematic diagram for the procedure below: B. % SO3 determination Dry the soluble sulfate sample at 100° C for 1-2 hours, and cool in desiccator. Weigh out 0.5 – 0.7 g (± 0.3 mg) duplicates sample. Transfer to 400-mL beakers. Dissolve each in 200 mL of dist. H2O + 4 mL of 6 m HCl. Precipitant is prepared by dissolving 1.3 g BaCl2 ∙ H2O in 100 mL water. Filter if solution is not perfectly clear. Heat the BaCl2 solution and sulfate sample solution nearly to boiling, and then add the entire amount to the HOT sulfate sample solution while stirring vigorously. Wash stirring rod with distilled water and include washings in your final mixture. Digest by letting stand 1-2 hours. Overnight standing is acceptable. Filter through an ash less filter paper of fine porosity (Whatman no. 42). Slowly pour the supernatant liquid through the filter paper.A mixture of pure BaCO3 and pure Na2CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO2 in the mixture and the weight of Li2CO3 that has the same neutralizing power as 1.000 g of the above mixture. Instructions: Include up to 4 decimal places See sample photo for the format of solution5.00 mL of stock solution is diluted to 25.00 mL, producing solution ALPHA. 10.00 mL of solution ALPHA is diluted to 25.00 mL, resulting in solution BETA. 10.00 mL of solution BETA is then diluted to 25.00 mL, producing solution GAMMA. dilution factor for ALPHA from stock solution = 0.167 dilution factor for BETA from ALPHA solution = 0.0476 part c and d?
- A mixture of pure BaCO3 and pure Na2CO3 weighs 1.000 g and has the total neutralizing power of 15.37 meq of CaCO3. Calculate the percentage of combined CO2 in the mixture and the weight of Li2CO3 that has the same neutralizing power as 1.000 g of the above mixture. Note: include up to 4 decimal places Please explain each stepObjective: To determine the percent NaCl (w/v) of a water sample 5.00 mL sample diluted to 50 mL solution 0.1000 M AgNO3 Volume of AgNO3 trial 1=15.30 mL trial 2=14.90 mL trial 3=15.10 ml1. Why is there a need to correct conductivity of the sample solution?2. Cite three possible sources of error in the experiment and discuss their effects on the computed ionization constant of the acetic acid. (See details below----- literature value- Ki, acetic acid= 1.75 x 10^-5). 3. What is the effect of dilution on the fraction of the acetic acid ionized?
- A 10.0mL (10.0g) sample of blood was found to contain lead at a concentration of 0.5ppm. What mass of lead was contained in the blood sample? (report answer in scientific notation) Please show the breakdown of how to do the problem as I get confused when steps aren't explained. Thank you!Methodology: Make schematic diagram for the procedure below B. % SO3 determination Dry the soluble sulfate sample at 100° C for 1-2 hours, and cool in desiccator. Weigh out 0.5 – 0.7 g (± 0.3 mg) duplicates sample. Transfer to 400-mL beakers. Dissolve each in 200 mL of dist. H2O + 4 mL of 6 m HCl. Precipitant is prepared by dissolving 1.3 g BaCl2 ∙ H2O in 100 mL water. Filter if solution is not perfectly clear. Heat the BaCl2 solution and sulfate sample solution nearly to boiling, and then add the entire amount to the HOT sulfate sample solution while stirring vigorously. Wash stirring rod with distilled water and include washings in your final mixture. Digest by letting stand 1-2 hours. Overnight standing is acceptable. Filter through an ash less filter paper of fine porosity (Whatman no. 42). Slowly pour the supernatant liquid through the filter paper.profile-image Time remaining: 00 : 09 : 27 Chemistry A group was given the responsibility of performing a recrystallization experiment in their laboratory to see if the three newly found solvents could purify and separate a mixture including compounds A and B. The following are the solubilities of the two compounds in g/100 mL of hot and cold solvents:Solubility in g/100 mL solvent A B B Solvent Hot Cold Hot Cold 1 4.60 1.10 5.30 1.90 2 6.40 5.80 8.40 1.10 3 3 9.70 3.30 6.80 What is the %recovery and %purity of A and B in the chosen solvent? Show solutions pls
- Scientist 1 analyzed the compounds first then gave it to scientist 2 for the next test. Scientist 2 needs to know the molar mass of the active compound. The concentration of the solution they created is twenty percentw/w from the solid active compound and it has a density of 1.40 grams per millilitre. Ten microliters were taken from this solution and mixed with one hundred ninety microliters of reagent and water. After analyzation, it showed that the compound's concentration is Five times ten raised to negative four M i. Find the concentration of the twenty percentw/w solution. The concentration must be in the form of molarityii. Explain the reason why the concentration of the solution was expressed as %w/w initially?iii. Determine the active compound's molar mass.You are given a container with Na3PO3 that is reportedly contaminated. You are asked by your supervisor to determine the percent purity of that sample in order to know the next measures to be taken by the plant. The following are the procedures that you need to do: a. Dissolve sample weighing 1 g in 35 mL water. b. Prepare solution with 45 mL 3% w/v HgCl2, 30 mL 10% w/v C2H3NaO2 and 10 mL CH3COOH. c. Digest sample then filter then rinse the precipitate that weighs 0.2857 g. d. Compute for the % purity.1. is pH scales is strictly btw 0 and 14? if not, why? 2. what is CSTR? is this heterogenous? is this concentration depends on location? 3. is steady state, mass can enter ot not? leave the control volume or not?