On this recommendation, a researcher wanted to estimate the mean sedentary time (sitting while watching TV, in a car, or while playing gadgets) of adolescents at 95% confidence level. In the study, a random sample of 25 adolescents spent an average of 8.76 hours per day being sedentary. Suppose that sedentary times are normally distributed with a standard deviation of 1.75 hour per day. ● The 95% confidence interval for the mean sedentary time (hours per day) of adolescents is [Select]
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- What is meant by the sample space of an experiment?To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected 200 people from San Diego and found that 101 were subscribed. a) Check that the assumptions are met for a confidence interval for proportions.To find the proportion of San Diegans subscribed to Disney+ in 2019, a researcher randomly selected 200 people from San Diego and found that 101 were subscribed. Find a 95% confidence interval estimate for the true proportion of San Diegans subscribed to Disney+. Round to four decimal places.
- A recent study among 150 street hawkers in Cape Town showed that 48 of them are of the opinion that the local regulations obstruct their business. a) Construct and interpret a 95% confidence interval based on this sample.1) A Gallup poll of 1015 randomly selected adults found that 69% would oppose a law that limited the size of soft drinks and other sugary beverages served in restaurants. Calculate and interpret a 95% confidence interval for the proportion of all adults that would oppose a law limiting the size of soft drinks.A joint USA Today/CNN/Gallup Poll in July 2020 indicated that of 832 white adults, 46% thought affirmative action has been good for the country and 44% thought it had not been good; the remaining 10% were undecided. Construct and interpret a 95% confidence interval for the true proportion of American white adults believing that affirmative action has been good.
- Suppose that a safety group surveyed 1,100 drivers. Among those surveyed, 65% said that careless or aggressive driving was the biggest threat on the road, and 25% said that cell phone usage by other drivers was the driving behavior that annoyed them the most. Based on these data and assuming that the sample was a simple random sample, construct and interpret a 95% confidence interval estimate for the true proportion in the population of all drivers who are annoyed by cell phone users. The confidence interval estimate is ??––––––??> (Round to three decimal places as needed. Use ascending order.) Interpret the confidence interval estimate. A. There is a 0.95 probability that the population proportion of drivers who are annoyed by cell phone users is in the interval. B. There is 95% confidence that the population proportion of drivers who are annoyed by cell phone users is in the interval. C. There is 95% confidence that the population proportion…In a sports poll, 142 of 500 randomly selected Americans indicated that they consider themselves to be baseball fans. Calculate a 98% confidence interval for the proportion of Americans who consider themselves to be baseball fans.A random sample of 180 men indicated that 50 were smokers, and a random sample of 150 women surveyed indicated that 39 smoked. Construct a 98% confidence interval for the true difference in proportions of male and female smokers.
- The production manager in an automobile plant is concerned with the number of cars that do not pass the final quality control inspection. In the last two hours he noted that in a sample of 120 cars only 92 were acceptable. The lower and upper limit of a 95% confidence interval for the true percentage of all cars that would not pass the final quality control inspection would be:Out of a sample of 1,450 people, 1,000 said they prefer to drive themselves to work rather than carpool. Construct a 95% confidence interval for the population mean of people who would rather drive themselves than carpool.