Problem 1 Yeast cells has been cultured on glucose (Table 1). The growth data follows the Monod Equation Table 1: Growth data for yeast cells Glucose concentration (mg/L) 7 10 15 40 1000 200 0.12 0.2 0.304 0.340 Specific growth rate (h:¹) 0.066 0.088 Observed yield, Y'x/s (g/g) 0.294 0.330 0.364 0.419 0.451 0.458 a) Calculate the maximum specific growth rate (µmax) and the substrate constant (Ks)
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- Yeast Catalase Experiment Questions: 1) What is the purpose of having a 0ml hydrogen peroxide group in a yeast catalase experiment? 2) What reactants contain yeast catalase: H2O2 or yeast mixture? 3) What gas is being given when catalase and hydrogen peroxide react?Hello! Can you please help me with the following: a. Draw the basic batch growth curve and label the four difference phases of growth and kinetics on the curve.b. Give a description of each phase on the curvec. Compare (less than, greater than, equal to, equal to zero) growth rate (Rg) and death rate (Rd) at each phase.d. What is the deceleration phase? Where is this phase on the curve (circle the location)?e. What does it mean that the exponential growth phase is 1st order? Please give the equation that represents the order of the exponential growth phase. Thank you!Problems 14 and 15: some of the exponents are unclear. Here they are: 14. Calculate vi and the degree of inhibition caused by a competitive inhibitor under the following conditions:(a) [S]=2x10-3 Mand[I]=2x10-3 M(b) [S]=4x10-4 Mand[I]=2x10-3 M (c) [S]=7.5x10-3 Mand[I]=10-5 MAssume that Km = 2 x 10-3 M, Ki = 1.5 x 10-4 M and Vmax = 270 nmoles x liter-1 x min-1.The degree of inhibition is the percent of the uninhibited velocity reached in the presence of the inhibitor. 15. (a) What concentration of competitive inhibitor is required to yield 75% inhibition at a substrate concentration of 1.5 x 10-3 M if Km =2.9x10-4 M and Ki =2x10-5 M? (b)Towhatconcentration must the substrate be increased to reestablish the velocity at theoriginal uninhibited value?
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- continuous disc stack centrifuge is operated at 5000 rpm for separation of tukers' yeast. At a feed rate of 60 min21, thirty of the cells are recovered. For operation at constant centrifuge speed, solids recovery is inversely proportional to the flow rate. (a) What flow rate is required to achieve 90% cell recovery if the centrifuge speed is maintained at 5000rpm thi What operating speed is required to achieve 90% recovery at a feed rate of 60 min211).Batch culture time prediction: A strain of Escherichia coli has been genetically modified to produce human protein. A batch culture is started by inoculating 12 g of cells into a 100 liters bubble column fermenter containing 10 g/l glucose. The culture does not exhibit a phase lag. The maximum specific growth rate of the cells is 0.9 h^-1, the glucose biomass yield is 0.575 g/g. Estimate the time required to reach the stationary phase.Asap possible solve all need solutions .no need explanation. Solve in 10mins
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