Propane reacts with oxygen to produce carbon dioxide and water according to thefollowing equation. Which ratio of components is correct?C3H8 +502 → 3CO2 + 4H₂O○ For each mole of propane that reacts, 5 moles of oxygen are produced.○ For each mole of oxygen that reacts, 3 moles of carbon dioxide are produced.○ For every 3 moles of carbon dioxide produced, 5 moles of oxygen react.○ For every 4 moles of water produced, 3 moles of propane react.

Answered: Propane reacts with oxygen to produce…

World of Chemistry, 3rd edition

3rd Edition

ISBN:9781133109655

Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste

Chapter9: Chemical Quantities

Section: Chapter Questions

Problem 66A

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Consider the unbalanced equation for the combustion of propane: :math>C3H8(g)+O2(g)CO2(g)+H2O(g) rst, balance the equation. Then, for a given amount of propane, write the mole ratios that would enable you to calculate the number of moles of each product as well as the number of moles of O2that would be involved in a complete reaction. Finally, show how these mole ratios would be applied if 0.55 mole of propane is combusted.
Classify each of the following statements as true or false: a Coefficients in a chemical equation express the molar proportions among both reactants and products. b A stoichiometry problem can be solved with an unbalanced equation. c In solving a stoichiometry problem, the change from quantity of given substance to quantity of wanted substance is based on masses. d Percentage yield is actual yield expressed as a percentage of ideal yield. e The quantity of product of any reaction can be calculated only through the moles of the limiting reactant. f rH is positive for an endothermic reaction and negative for an exothermic reaction.
For each of the following balanced reactions, calculate how many moles of each product would be produced by complete conversion of 0.50 mole of the reactant indicated in boldface. Indicate clearly the mole ratio used for the conversion. msp;2H2O(l)2H2O(l)+O2(g) msp;2KClO3(s)2KCl(s)+3O2(g) msp;2Al(s)+6HCl(aq)2AlCl3(aq)+3H2(g) msp;C3H8(g)+5O2(g)3CO2(g)+4H2O(g)
Freon-12, CCl2F2, is prepared from CCl4 by reaction with HF. The other product of this reaction is HCl. Outline the steps needed to determine the percent yield of a reaction that produces 12.5 g of CCl2F2 from 32.9 g of Cd4. Freon-12 has been banned and is no longer used as a refrigerant because it catalyzes the decomposition of ozone and has a very long lifetime in the atmosphere. Determine the percent yield.
Explain how one determines which reactant in a process is the limiting reactant. Does this depend only on the masses of the reactant present? Give an example of how to determine the limiting reactant by using a Before-Change-After (RCA) table with a balanced chemical equation and reactant starling amounts.
3.84 The picture shown depicts the species present at the start of a combustion reaction between methane, CH4, and oxygen, O2. (a) Draw the resulting state after this set of re- actants has reacted as far as possible. (b) Use the drawings to explain the stoichiometry represented in the balanced chemical equation for the combustion of methane.
Balance the following chemical equation, and then answer the question below. :math>CuSO4(aq)+KI(s)CuI(s)+I2(s)+K2SO4(aq) ich reactant is the limiting reactant? Choose the best answer. th CuSO4and Kl are equally limiting because they react in a 1:1 mole ratio. i>CuSO4is the limiting reactant because only 2 moles are available compared with 4 moles of Kl. i>Kl is the limiting reactant because it is present in excess. i>Neither CuSO4 nor Kl is a limiting reactant because 6 total moles are present on the reactant side compared with 5 total moles on the product side. i>The limiting reactant cannot be determined because the starting amounts are not given.
4.37 The theoretical yield and the actual yield for various reactions are given below. Determine the corresponding percentage yields. Theoretical Yield Actual Yield Reaction 1 35.0 g 12.8 g Reaction 2 9.3 g 120 mg Reaction 3 3.7 metric tons 1250 kg Reaction 4 40.0 g 41.0 g
For the chemical reaction Sb2S3+6HCl2SbCl3+3H2S write the conversion factor that would be needed to do each of the following one-step conversions. a. Moles of SbCl3 to moles of H2S b. Moles of Sb2S3 to moles of HCl c. Moles of H2S to moles of HCl d. Moles of Sb2S3 to moles of SbCl3
Ammonia can be formed by a direct reaction of nitrogen and hydrogen. N2(g) + 3 H2(g) 2 NH3(g) A tiny portion of the starting mixture is represented by the diagram, where the blue circles represent N and the white circles represent H. Which of these represents the product mixture? For the reaction of the given sample, which of these statements is true? (a) N2 is the limiting reactant. (b) H2 is the limiting reactant. (c) NH, is the limiting reactant. (d) No reactant is limiting: they are present in the correct stoichiometric ratio.
For each of the following unbalanced reactions, suppose exactly 5.00 g of each reactant is taken. Determine which reactant is limiting, and also determine what mass of the excess reagent will remain after the limiting reactant is consumed. Na2B4O7(s) + H2SO4(o H3BOj(j) + Na2SO4(u CaC,(s) + H2O(/) Ca(OH)2(s) + C2H2(g) NaCl(s) + H2SO4(/> HCl(g) + Na2SO4(s) SiO2(s) + C(x) —> Si(/) + CO(g)
The gaseous hydrocarbon acetylene, C2H2, is used in welders’ torches because of the large amount of heat released when acetylene burns with oxygen. :math>2C2H2(g)+5O2(g)4CO2(g)+2H2O(g) w many grams of oxygen gas are needed for the complete combustion of 150 g of acetylene?

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