Punnett Square Practice Worksheet 1) For each of the genotypes (AA, Aa or aa) below determine what the phenotype would be. Purple flowers are dominant to white flowers. PP Hairy knuckles are dominant to non-hairy knuckles in humans. HH_ Pp_ - P. Hh hh Bobtails in cats are recessive. Normal tails are dominant. TT Tt. tt 2) For each of the following write whether it is homozygous dominant (HD), heterozygous (H), or homozygous recessive (HR). AA gg li TT Pp. tt_ Use the following information for questions 3-5: In dogs, the gene for fur color has two autosomal alleles. The dominant allele (F)

Punnett Square Practice Worksheet 1) For each of the genotypes (AA, Aa or aa) below determine what the phenotype would be. Purple flowers are dominant to white flowers. PP Hairy knuckles are dominant to non-hairy knuckles in humans. HH_ Pp_ - P. Hh hh Bobtails in cats are recessive. Normal tails are dominant. TT Tt. tt 2) For each of the following write whether it is homozygous dominant (HD), heterozygous (H), or homozygous recessive (HR). AA gg li TT Pp. tt_ Use the following information for questions 3-5: In dogs, the gene for fur color has two autosomal alleles. The dominant allele (F)

Name: Name:Date:Punnett Square Practice Worksheet1) For each of the genotyp
Uploaded: 2024-03-20T06:43:04.000Z
Channel: Bartleby
Description: Name:Date:Punnett Square Practice Worksheet1) For each of the genotypes (AA, Aa or aa) below determine what thephenotype would be.Purple flowers are dominant to white flowers.PPHairy knuckles are dominant to non-hairy knuckles in humans.HHPp.p.HhhhB

Human Heredity: Principles and Issues (MindTap Course List)

11th Edition

ISBN:9781305251052

Author:Michael Cummings

Publisher:Michael Cummings

Chapter18: Genetics Of Behavior

Section: Chapter Questions

Problem 14QP: A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known...

See similar textbooks

Similar questions

.) A female poodle with green eyes (recessive) and yellow spots on her tongue (recessive) was bredwith a male poodle who was the wild-type phenotype but hybrid genotype for those same two traits.In a series of litters, this breeding pair gave birth to the following 85 puppies:39 Normal eyes, normal tongue36 Green eyes, yellow-spot tongue6 Green eyes, normal tongue4 Normal eyes, yellow-spot tonguea.) Use the symbols grn and grn+ for the green eyes gene, and yel and yel for the yellow tonguegene and give the genotypes of the parents of this cross. (Remember, each parent has twoalleles for each gene.)b.) Now give the expected genotypes of the offspring.c.) If these two genes were unlinked, given the way the cross was constructed, what ratio wouldyou expect to see among the four categories of offspring shown here?d.) Now match up the expected phenotypes (answer to 2b) with the actual offspring.e.) Which categories of dogs are “parental types” and which are recombinant types?f.) Do these…
Consider the following scenario: A man without freckles (freckles are a dominant trait, determined by the dominant allele “F”) is a carrier of cystic fibrosis (recall that CF is a recessive trait, determined by the recessive allele "a"), mates with a woman whose genotype is heterozygous for freckles and is also a carrier of CF. Assume the two genes in question are in different chromosomes and, therefore, assort independently. Complete the following Punnett square to generate the offspring probabilities from this couple, by entering the genotypes of the parents, the gametes, and the offspring for the two traits described above. (4) Father’s genotype ffAa Mother’s genotypeFfAa ● Sperm: fA ● Sperm: fa ● Sperm: fA ● Sperm: fa ● Egg: FA ● Egg: fA ● Egg: Fa ● Egg: fa What is the probability for this couple to have a child with freckles? What is the…
Using the punnet square (di-hybrid cross) solve the following: In a certain breed of dog, the dominant, B, is required for black fur; and it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic gene to the color locus and can inhibit pigment formation. The epistatic recessive allele, i, on the other hand, permits pigment deposition in the fur. -Cross the following parents: bbIi x BBIi 1st Question to answer ---- How many different possible genotypes are there among the offspring? 2nd Question to answer ---- How many of the offspring could be black? 3rd Question to answer ---- How many of the offspring could be brown? 4th Question to answer ---- How many of the offspring could be albino (white)? Different Possible Genotypes Black Offspring Brown Offspring Albino/White Offspring
A pedigree analysis was performed on the family of a man with schizophrenia. Based on the known concordance statistics, would his MZ twin be at high risk for the disease? Would the twins risk decrease if he were raised in an environment different from that of his schizophrenic brother?
A cross was performed using Drosophila melanogaster involving a female known to be heterozygous for both ebony body and sepia eyes and a male known to be homozygous for both of these recessive traits. The following data was produced from the cross. Test these data to determine if they are significantly different from the expected phenotypic ratio. Remember to use the 5% level of significance Wild eye Wild body – 102, Wild eye Ebony body – 94, Sepia eye Wild body – 100, Sepia eye Ebony body – 93. Your answer should include the hypothesized cross in genotypes, the Chi-squared value, the critical value and whether you reject or do not reject.
In rabbits, the gene for fur color is multiallelic. Agouti (C) is dominant to chinchilla (Cch), chinchillas is dominant to himalaya (Ch), and himalaya is dominant to albino (c). Determine the genotypes of each corresponding phenotypes. Please show the solution.
Spiky and Banded are two dominant, autosomal traits in purple snails. You cross a snail that exhibits both these traits (S_ B_) with a homozygous recessive snail (ssbb) . Spiky chin and banded (S_ B_) The resulting offspring are the following phenotypes: Spiky, Banded 153Smooth, Banded 54Spiky, Unbanded 70Smooth, Unbanded 171 (a) Test whether these two loci are linked with a chi-square test (show your work).
Using the punnet square (di-hybrid cross) solve the following: In a certain breed of dog, the dominant, B, is required for black fur; and it’s recessive, b, produces brown fur. However, the dominant, I is the epistatic gene to the color locus and can inhibit pigment formation. The epistatic recessive allele, i, on the other hand, permits pigment deposition in the fur. -Cross the following parents: bbIi x BBIi 4th Question: How many of the offspring could be albino (white)?
REad and analyzed the following genetic problem. Show complete solution (Genotypes of P, Punnet Square and GR,PR). 1. In the garden peas, green pod color is dominant over yellow pods. Also, round seed shape is dominant over wrinkled seed. Cross fertilization was done between a pea that is homozygous dominant for pod color with heterozygous round shape and another pea that is heterozygous for both pod color and seed shape. Determine the genotypic and phenotypic ratio of teh offspring.
In goats, black fur is dominant to red fur. The gene for this trait can be described as Bb (if you forgot why this is so, go back and reread the background information at the beginning of this exercise). A homozygous black female goat (nanny) is crossed with a heterozygous male (billy). 1 What is the genotype of the nanny? Fill input: What is the phenotype of the nanny?
While studying the genetics of the "Cute Faced Bat" face structure gene, three alleles ) are identified that produce 6 genotypes and 4 phenotypes “Cute”, “Super Cute Nose”, “Super Cute Face”, and “Super, Duper Cute” (equally expressing both Super Cute Face and Super Cute Nose). Given these observations, what can you conclude about the allele interactions?
The colors of chicken feathers follow a codominant pattern. Both Black (B) and White (W) feathers are dominant phenotypes while checkered (BW) is the heterozygous phenotype. Show a cross between 2 checkered chickens. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %: