Question: You mix 42.00 mL of 6.20 Pb(NO3)2 with 23.00 mL of 1.70 NaCl. A precipitate forms. Assuming the reaction has a 100% yield. How many grams of precipitate are formed? (I had this answered twice before, but both provided different answers which makes me suspicious. please double check work) Answering process (VERY IMPORTANT): please make sure that you answer in this format, so that I can understand the process best. - What are you solving for? What should be the units of your final answer? - What information are you given? - What information do you need? - How will you connect the information you have and the information you need to solve this problem? (Provide a unit plan) - Solve the problem. Be sure to show all units and write clearly - Does your answer make sense? How do you know

Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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You mix 42.00 mL of 6.20 Pb(NO3)2 with 23.00 mL of 1.70 NaCl. A precipitate forms. Assuming the reaction has a 100% yield. How many grams of precipitate are formed? (I had this answered twice before, but both provided different answers which makes me suspicious. please double check work)

Answering process (VERY IMPORTANT):

please make sure that you answer in this format, so that I can understand the process best.

- What are you solving for? What should be the units of your final answer?

- What information are you given?

- What information do you need?

- How will you connect the information you have and the information you need to solve this problem? (Provide a unit plan)

- Solve the problem. Be sure to show all units and write clearly

- Does your answer make sense? How do you know?

Expert Solution
Step 1

The moles of the solution always remains constant. there is no effect of volume change or concentration change by dilution on final moles of solution. These moles are bases on the relation of M1V1=M2V2. Here, 'M' stands for concentration of the initial solution in moles/L and 'V' is Volume of solution.

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