Show that if it can be assumed that there is a pre-equilibrium involving step (1), the rate of formation of ethylene oxide is v = k,K[CH,CICH,OH][OH ], where K is the equilibrium constant for the first step and k, is the rate constant for the second step. E17E.2(b) 'The mechanism for the reaction between 2-chloroethanol, CH,CICH,OH, and hydroxide ions in aqueous solution to form ethylene oxide, (CH,CH,)0, is thought to consist of the steps (1) CH,CICH,OH+OH 2CH,CICH,O¯+H,O (2) CH,CICH,O¯ –→(CH,CH,)O+CI

Show that if it can be assumed that there is a pre-equilibrium involving step (1), the rate of formation of ethylene oxide is v = k,K[CH,CICH,OH][OH ], where K is the equilibrium constant for the first step and k, is the rate constant for the second step. E17E.2(b) 'The mechanism for the reaction between 2-chloroethanol, CH,CICH,OH, and hydroxide ions in aqueous solution to form ethylene oxide, (CH,CH,)0, is thought to consist of the steps (1) CH,CICH,OH+OH 2CH,CICH,O¯+H,O (2) CH,CICH,O¯ –→(CH,CH,)O+CI

Introduction to General, Organic and Biochemistry

11th Edition

ISBN:9781285869759

Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Publisher:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres

Chapter7: Reaction Rates And Chemical Equilibrium

Section: Chapter Questions

Problem 7.42P

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