Step 1 of 2:) Applying 18e- rule to determination of bonding of NO ligand. Step 2 of 2:) [FeccN)s NO ]?- x+5-1) +0= -2 xニ+3 Fe3+ = 4s03d5 oppying 18e rule [ FecCN)5NO]?- 5+5x2 + =18 15+x=18 H=3 3 alectro n doror NO is a leaner
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- The accompanying data (1.00-cm cells) were obtained for the spectrophotometric titration 10.00 mL of Pd(II) with 2.44 10-4 M Nitroso R(O. W Rollins and M. M. Oldham, Anal. chem .,1971, 43, 262, DOI: 10.1021/ac60297a026). Calculate the concentration of the Pd(II) solution, given that the ligand-to-cation ratio in the colored product is 2:1At 580 nm, which is the wavelength of its maximum absorption, the complex Fe(SCN)2+ has a molar absorptivity of 7.00 I03L cm-1 mol-1.Calculate (a) the absorbance of a 4.47 10-5 M solution of the complex at 580 nm in a 1.00-cm cell. (b) the absorbance of a solution in a 2.50-cm cell in which the concentration of the complex is one half that in(a). (c) the percent transmittance of the solutions described in (a) and (b). (d) the absorbance of a solution that has half the transmittance of that described in (a)..A. w: Mn= 25, Co= 27, Ni= 28, Zn= 30 ------------ Complex K3[Mn(C204)3] Highly distorted. O Low distorted. O not distorted. O The magnetic moment of the -------------- complex [Ni(en)3]CI2 is * 0Bm 2.8 BM 1.8 BM O OO0O0 3.8 BM
- 1. a. Define the expressions of K1-6 and β1-6 for: Ni(H2O)62+ + 6 NH3 -------> Ni(NH3)62+ + 6 H2O <--------- b. To which ligand will Ni2+ have a higher affinity and why: PhNH2 or PhSH.Please help me fill the remaining spaces. The spaces marked with NA don't need to be calculate. Name Molecular Weight Amounts used mmol Equivalents M.P or BP (C) Density (g/mL) Indene 116.16 .5mL MP=-2 BP=181-182 .996 Borane-tetrahydrofuran Complex 85.94 2.8mL 1 MP= -108 BP=66 NA 30% Hydrogen Peroxide 34.01 1mL MP= -33 BP=108 NA 3 M NaOH(aq) 40 .7mL MP=318 BP=1390 NA Diethyl Ether 74.12 NA NA NA BP=75-78 .902 Hexanes 86.17 NA NA NA BP=65.5-68.3 .659 Potassium Permanganate 158.03 NA NA NA BP=100 1.0 1-Indanol (Product) 134.13 NA MP=50-54 NA 2-Indanol (Product) Same as Above Same as Above Same as Above NA MP=68-71 NAAg+ + ligand L --> Ag_ligandL_Complex K_bind = ??? The virtual lab below contains a 1.00M flask of 'Ligand L' along with a bottle of solid silver chloride. Perform an experiment in the virtual lab to determine the binding constant for this ligand (K_bind for the above reaction). ou will need to use your knowldedge of solubility to determine tthe binding constant. The Ksp for Silver Chloride is: 1.830e-10. Agcl 0.971351 What is the binding constant for this ligand (Please use three significant figures for your answer)
- Given the Information that Fe3++Y4FeYKi=1.01025Cu2++Y4CuY2Ki=6.31018 and the further information that, among the several reactants and products, only CuY2- absorbs radiationat 750 nm, describe how Cu(II) could be used as an indicator for the photometric titration of Fe(III) with H2Y2-. Reaction:+ Fe3++ H2Y2- FeY- + 2H+.Zinc(II) and the ligand L form a 1:1 complex that absorbs strongly at 600 nm. As long as the molar concentration of L exceeds that of zinc(II) by a factor of 5, the absorbance depends only on the cation concentration. Neither zinc(II) nor L absorbs at 600 nm. A solution that is 1.59 10-4 M in zinc(II) and 1.00 10-3 M in L has an absorbance of 0.352 in a 1.00-cm cell at 600 nm. Calculate (a) the percent transmittance of this solution. (b) the percent transmittance of this solution in a 2.50-cm cell. (c) the molar absorptivity of the complex.A FeSCN complex, whose maximum absorbance is at a λ of 580 nm, has a molar extinction coefficient of 5×103 M-1cm-1 . A solution is measured with a 25 mm cell at the same λ , obtaining 20.6% T. Calculate the concentration in [ppm] of the complex in the solution.
- Vanadium has two isotopes (50V, 0.25%; 51V,99.75%). The EPR spectrum of an aqueous solutionof [VO(OH2)5]2+ shows an 8-line pattern, andg-values of gzz=1.932, gxx = 1.979 and gyy=1.979were determined. What can you deduce from the data?Cation Elimination Test ObservationsAdded Reagents and their ObservationsNaOH = Light blue pptExcess NaOH = undissolved pptNH3 = Blue pptExcess NH3 = Dissolved precipitation ; deep blue complex1. What are the possible Cation/s present?Cu2+ , Zn2+ , Ca2+ , Fe3+ , NH4+ Cation Confirmatory test ObservationsAdded Reagents and Observation:Excess NH3 = Dissolved precipitation ; deep blue complexKSCN = NVRK4Fe(CN)6 = NVRK4Fe(CN)6 = NVRNa2C2O4 = White precipitationNaOH (in evap dish) = NVR2. what are the possible ion/s present? Show a flowchart.Cu2+ , Zn2+ , Ca2+ , Fe3+ , NH4+Nickel bis-dimethylglyoximate complex was deposited with a weight of (4.869g) with the filter paper from the base medium from adding (10ml) of hot DMG to a salt of nickel chloride at weight (0.78g), find the percentage of nickel ion. Note that the weight of the filter paper (1.30g). At.Wt.: Ni= 58.69 g/mol, C= 12 g/mol, O=16 g/mol, H=1 g/mol, N=14 g/mol