Suppose a liver extract capable of carrying out normal metabolic reactions (including gluconeogenesis) is incubated with pyruvate partially labeled with deuterium at the methyl group (see below: D= deuterium, i.e., H-2) a) Explain why the oxaloacetate formed in step 1 of gluconeogenesis is only partially labeled (i.e., some of the oxaloacetate is labeled and some is not). b) Where would the label be found in glucose?
Suppose a liver extract capable of carrying out normal metabolic reactions (including gluconeogenesis) is incubated with pyruvate partially labeled with deuterium at the methyl group (see below: D= deuterium, i.e., H-2) a) Explain why the oxaloacetate formed in step 1 of gluconeogenesis is only partially labeled (i.e., some of the oxaloacetate is labeled and some is not). b) Where would the label be found in glucose?
Chapter5: Phlebotomy Equipment
Section: Chapter Questions
Problem 1.2E
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Suppose a liver extract capable of carrying out normal
a) Explain why the oxaloacetate formed in step 1 of gluconeogenesis is only partially labeled (i.e., some of the oxaloacetate is labeled and some is not).
b) Where would the label be found in glucose?
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