Suppose memory holds the following data values in these addresses: Address: Data: 1000: 25 1004: 33 1008: 48 Suppose the register file holds the following data in registers $ through $3: $0: 0 $1: 1000 $2:8 $3:4 What values are in $1 and $2 after this instruction is executed Iw $2, 8($1) O $1: 1008, $2: 48 $1: 1000, $2: 48 $1: 1000, $2: 1008
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- _____ is a CPU design technique in which instruction execution is divided into multiple stages and different instructions can execute in different stages simultaneously.Most Intel CPUs use the __________, in which each memory address is represented by two integers.A(n) ________________ instruction always alters the instruction execution sequence. A(n) ______________ instruction alters the instruction execution sequence only if a specified Condition is true.
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- 1. T/F - if (B)=006000 (PC)=003600 (X)=000090, for the machine instruction 0x032026, the target address is 003000.2. T/F – PC register stores the return address for subroutine jump.3. T/F – S register contains a variety of information such as condition code.4. T/F – INPUT WORD 1034 – This means Operating system should reserve 1034 bytes in memory5. T/F - In a two pass assembler, adding literals to literal table and address resolution of local symbol are done using first pass and second pass respectively.Suppose that each of the 4 processors in a shared memory multi-processor system is rated at 400 MIPS. A program contains a purely sequential part that accounts for 22% of the program’s execution time on a single processor. The remaining code can be partitioned into three independent parts (A, B, and C). Running on a single processor, part A accounts for 30% of the program’s execution time, part B accounts for 18%, and part C accounts for 30%. What is the apparent MIPS rating for the program if it is run on the 4-processor system and the sequential part must be completed before any of the remaining independent parts (A, B or C) can run in parallel?hi can u anwser this qustion plesc ? Consider a Computer which has a memory which is capable of storing 4096 K words and each word in memory can be of size 32 bits. The computer supports a total of “K” addressing modes, and it has “M” computer registers. The computer supports instructions, where each instruction consists of following fields: Mode Operation code Register Register Memory AddressGiven that each instruction will be stored in one memory word, discuss with a suitable diagram the format of instruction by specifying number of bits for each field of instruction. Discuss each field of instruction.Note: Choose your own values for K (number of addressing modes) and M (number of Registers) k=8 m=50
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