translate the c++ code into pep/9 assembly language #include using namespace std; void minimum (int i1, int i2) {     if (i1 < i2)         cout << i1 << " is less than " << i2 << endl;    else if (i1 > i2)         cout << i2 << " is less than " << i1 << endl;     else         cout << i1 << " equals " << i2 << endl; } int main () {     int n, m;     cout << "Enter two integers: ";     cin >> n >> m;     minimum (n, m);     return 0;

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>> IN C PROGRAMMING LANGUAGE ONLY << COPY OF DEFAULT CODE, ADD SOLUTION INTO CODE IN C   #include <stdio.h>#include <stdlib.h>#include <string.h> #include "GVDie.h" int RollSpecificNumber(GVDie die, int num, int goal) {/* Type your code here. */} int main() {GVDie die = InitGVDie(); // Create a GVDie variabledie = SetSeed(15, die); // Set the GVDie variable with seed value 15int num;int goal;int rolls;  scanf("%d", &num);scanf("%d", &goal);rolls = RollSpecificNumber(die, num, goal); // Should return the number of rolls to reach total.printf("It took %d rolls to get a \"%d\" %d times.\n", rolls, num, goal); return 0;}

Convert the following c++ code  into pep9 assembly language.   #include <iostream> using namespace std; void times(int& prod, int mpr, int mcand) { prod = 0; while (mpr != 0) { if (mpr % 2 == 1) prod = prod + mcand; mpr /= 2; mcand *= 2; } } int main(){ int product, n, m; cout << "Enter two numbers: "; cin >> n >> m; times(product, n, m); cout << "Product: " << product << endl; return 0; }

Problem 1. In C/C++ programming language, write down the lines of codes (and figure) to show -(a) assignment-by-sharing(b) dangling referenceProblem 2. Show the correspondingcodecontents in memory for themainmethod and draw thestackcontents while themainmethod starts execution and reaches at line 12. 1 #include<iostream> 2 using namespace std ; 3 int main () 4 { 5 int i ; 6 short j ; 7 char k ; 8 i = 30; 9 j = i ; 10 k = ( char ) j ; 11 i = k ; 12 13 return 0; 14 }   Problem 3. (a) In C++, write down themainmethod including aforloop. The body of theforloop includes the followings :anifconditionan array (of any type & of any size)a structure variable (with at least two variables of any type) (b) Show the correspondingcodecontents in memory for themainmethod and drawthestackcontents while themainmethod starts execution and reaches at theline prior to return from yourmainmethod of Problem 3(a). (c) Create a symbol table structure (dynamic scoping) at the line before…

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Convert the following C++ programs into Pep/9 assembly #include <iostream> using namespace std; int minimum (int i1, int i2){if (i1 < i2)return i1;elsereturn i2;}int main (){int n, m;cin >> n >> m;cout << "Minimum: " << minimum (n, m) << endl;return 0;} Submit: Pep/9 source code along with screen capture showing it running in the Pep simulator

Translate the following C program into NASM.   #include <stdio.h> int ary[] = {12, 40, -2, 89, 35, -7, 6}; int main() {      int sum = 0;      int highest = 0;      for (int x = 0; x < 7; x++) {          if (highest < ary[x])               highest = ary[x];          sum += ary[x];      }      printf("Sum is %d\n", sum);      printf("Highest value is %d\n", highest); } Use indexing (the [ebx+esi] or [ebx+edi] form). You can have several “dw” values on the same line. Use the “loop” command.

translate the following C++ program into Pep/9 Assembly. #include<iostream> using namespace std; void showNext(int age){  int nextYr;  nextYr = age + 1;  cout << "Age:" << age<< endl;  cout << "Age next year: "       << nextYr << endl;}int main() {  int myAge;  cout << "Enter age: ";  cin >> myAge;  showNext (myAge);  return 0;}

PEP/9 Translate the following C++ program into assembly language:  #include <iostream> using namespace std; int main() {   char letter;   int countA = 0,        countB = 0,        countC = 0;   cin >> letter;   do {      switch (letter) {         case 'A' : countA++; break;         case 'B' : countB++; break;         case 'C' : countC++; break;       }      cin >> letter;   } while (letter != 'X');   cout << "Number of A's " << countA << endl          << "Number of B's " << countB << endl          << "Number of C's " << countC << endl;   return 0; } Use local variables (except for messages, of course) and the branch indexed for the switch statement.