Trial 1 Trial 2 Volume of sample analyzed (mL) 25.00 25.00 Initial buret reading (mL) 0.75 26.03 Final buret reading (mL) 25.80 50.40

Q: [OH ] = 3.7×10-12 M Express your answer using two significant figures. H&O'] = Submit Request Answer

A:

Q: Acetic acid percentages in five vinegar samples were 4.98, 4.86, 4.97, 4.99. 5.08, 5.11, 4.97, 5.32…

A: To determine if any value can be rejected, we need to use Q-test.

Q: Br 3H 1H 6. 4 O ppm Answer Bank 1H 4H 2H 3H Incorrect

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Q: Dosage (mg/L) 1 2 Residual Cl₂ (mg/L) 0.2 0.45 3 1.05 لله 4 2.75 5 4.5 6 5.15 7 6.03

A: In the given problem we need to determine the break point dose of chlorine.

Q: Concentration iron(III) nitrate 0.35000 [Fe(NO3)3] (M) Color of iron(III) nitrate yellow…

A: Given : Concentration of Fe(NO3)3 = 0.35000 M Volume of Fe(NO3)3 solution used = 10.00 mL = 0.0100 L…

Q: The content of acetylsalicylic acid is determined by liquid chromatography/Uv, the quantification is…

A: We are given the concentration(mg/mL) and Rta data for the standard solutions.  First, we have to…

Q: Trial 1 Trial 2 Trial 3 Volume of Sample (mL) 55.00 55.00 55.00 Final Volume of EDTA (mL) 7.90 15.40…

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Q: Experiment Temprature/K / Baute Constant /51 متكلل 3ܩ3 -ܛܠ ܐ ܠܰܩܠܫܬ17 -kz 333 ܒܟܠ Cost ܐ ܬ ܬܠ ܘ ܬ.…

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Q: Initial temp: 19.06 C trial 1: 0.5 M concentration trial 2 : 1.0 M concentration 200 mL of HCl…

A: trial 1: 0.5 M concentration 200 mL of HCl and 200 mL of NaOH are combined in an insulated…

Q: (a) During the analysis of water sample by argentometric titration, results obtained are as follows:…

A: Argentometric titrations are done using silver nitrate solution. It is usually done to determine…

Q: Trial 1 Trial 2 Mass of KHP used 0.16 KHP 0.18 KHP Initial Buret reading for your NaOH 0.00 mL 7.46…

A: Trial 1. Mass of KHP ( Potassium hydrogen phthalate) used = 0.16 g Moles of KHP used = 0.16 g/204.22…

Q: TRIAL 1 TRIAL 2 TRIAL 3 Wt. of vinegar sample 8.2000 g 8.1000 g 8.2500 g Vol. of vinegar sample…

A: Since you have posted multiple questions, we are entitled to answer the first only.

Q: CHEM 181 Experiment #5 Part B Calculate the approximate volume of vinegar to react with 25 mL of 0.1…

A: Molarity (M) = Numer of moles of soluteVolume of solution (in L)Number of moles can be calculated…

Q: Sample Analysis Source of Water sample:Tap Water   Molarity of Na2S2O3 1 2 3   0.0243 0.0245…

A: The amount of dissolved oxygen present in water is one of the parameters that is used to describe…

Q: Trial 1 Concentration of NaOH: 6.00M Concentration of HC1: 0.800M mass of tablet: 1.294 g Initial…

A: The neutralization reaction between NaOH and HCl can be represented as: NaOH+HCl→NaCl+H2O

Q: Using the information below:                                                     Trial 1…

A: Using the information given : Student said the average volume of NaOH is 40.0 ml

Q: Trial 1 Trial 2 Trial 3 Inital volume NaOH (mL) 50.00 50.00 50.00 Final volume NaOH (mL) 14.68 8.91…

A: Given: Initial volume of NaOH =I1 = 50.00mL Final volume of NaOH = F1 = 14.68mL Volume of NaOH used…

Q: Trial 1 Trial 2 Concentration of iodide solution (mM) 150.6 150.6 Concentration of thiosulfate…

A: Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Q: TRIAL 1 TRIAL 2 TRIAL 3 Mass of Vitamin C (mg) 0.011 g/11 mg 0.012 g/12 mg 0.011g/ 11 mg Initial…

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Q: Trial 1 Trial 2 20.1 ML 20.1 ML Volume of Na3PO4 solution: Volume of BaCl2 solution: 20ML 1G.99…

A: Given: Precipitate: Ba3(PO4)2 molar mass of Ba3(PO4)2 = 601.93 g/mol

Q: Trial 1 Trial 2 Trial 3 Molarity NaOH Volume of vineqar 0.25 M 20.00 mL 20.00 mL 20.00 mL Volume of…

A: Acetic acid in vinegar can be titrated against NaOH.

Q: Trial [A]o [B] Rate (M/min) 1 0.40 0.20 0.12 2 0.20 0.20 0.030 3 0.40 0.40 0.24 4 0.60 0.40 0.54

A: Let order with respect to A is x and order with respect to B is y

Q: CHEM 181 Experiment #S Part B Calculate the approximate volume of vinegar to react with 25 mL of 0.1…

A: Molar mass of acetic acid = 60.052 g/mol Trial 1 :Mass of acetic acid in vinegar sample = moles of…

Q: TRIAL 1 TRIAL 2 TRIAL 3 Mass of Vitamin C (mg) 0.011 g/ 11 mg 0.012 g/12 mg 0.011g/ 11 mg Initial…

A: Ascorbic acid + I2    gives     2 I- + Dehydroascorbic acid So, 1 mol vitamin C reacts with 1 mol of…

Q: I Review | Constants | Part A 50.0 mL of 0.15 M HCHO2 with 80.0 mL of 0.12 M NaCHO2 Express your…

A:

Q: Question attached

A: It is given that the molarity of NaOH solution is 0.100 M and volume of vinegar sample taken is 5…

Q: Table 5.1 (report)Sample DistanceFe^3+ (5.8)Co^2+ (0.8)Cu^2+ (3.0)Mixture (0.8)(3.0)(5.8)Unknown…

A: Rf value can be determined as the distance travelled by the solvent divided by its mobile phase can…

Q: Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 1.15 2.05 1.14 Molarity of NaOH (M) 0.100 0.100…

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Q: 6 Measuring Mass of Monoprotic Unknown Acid Trial 1 Trial 2 Trial 3 8 Mass of unknown acid 10 0.3059…

A: Since this is a monoprotic acid (HA), it will react with 1 NaOH.  Balanced equation: HA(aq) +…

Q: Parameters Trial 1 Trial 2 Mass of sample, ml 20 20 Concentration of standard AGNO3 0.06090 0.06090…

A: Given: Concentration of AgNO3 = 0.0609 M Volume of sample of NaCl used = 20 mL Initial volume of…

Q: Observations: Table 1: Estimation of DO. SI No Volume of water Initial sample (ml) burette Final…

A: The experiment is given as follows:

Q: Table 2: Masses of compounds used and observations NaCI CusO+-5H20 (NH4)2Fe(SO4)2 Appearance of…

A: Mass of compounds used: For NaCl = 12.8364 - 11.6023 = 1.2341 gms For CuSO4.5H2O = 12.7398 - 11.4888…

Q: TRIAL 1 TRIAL 2 TRIAL 3 Mass of Vitamin C (mg) 11 mg 12mg 11mg Initial buret reading of lodine…

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Q: Conc. of NaOH: TRIAL 1 TRIAL 2 TRIAL 3 Mass of flask 81.061 g 69.692 g 96.039 g Mass of flask and…

A: We are given the table in the question: By checking the values from it we will find the required…

Q: Trial A Trial B Trial C No of drops Mass of system (g) No of drops Mass of system (g) No of drops…

A: Equvalence point is at which drop pH,a sudden pH changes happen.

Q: Trial 1 Initial Burette 1ml Reading (mL) Endpoint (mL) 11.75 Endpoint (pH) 12.91 10.56 Equivalence…

A: According to the Molarity formula - M = Moles of NaOH / Volume of…

Q: Quantity Trial 1 Trial 2 Trial 3 MNAOH (exact concentration) 1.189 1.189 1.189 Vinitial buret…

A: Note : Since you have asked multiple question, we will solve the first question for you. If youwant…

Q: Trial 1 2 3 S Final Volume Reading NAOH (ml) 36.65 38.23 35.80 Initial Volume Reading NaOH (ml) Net…

A: Standardization of sodium hydroxide

Q: Trial 1 Trial 2 (Data Collected by (Data Collected by Group Member 1) Group Member 2) Concentration…

A:

Q: TRial 1 Trial 2 Trial 3   0.1 N HCl 0.1 N NaOH 0.1 N HCl 0.1 N NaOH 0.1 N HCl 0.1 N NaOH…

A: Given that, the tritation of 0.1 N of HCl by 0.1 N of NaOH. The data table is shown below   Trial…

Q: Volume HCl (mL) 25.00 а. 0.00 b. Initial buret reading (mL) 25.40 c. Final buret reading (mL) 25.40…

A: Equation  NaOH(aq) + HCl (aq) ——> NaCl (aq) + H2O(l)   Molarity = no. of moles / volume (Lt)

Q: Limiting reagent   Calculated mass of excess reagent remaining in the mixture after reaction, g…

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Q: Trial I Trial II Final reading HCI 26. 40 ml 27.10 ml Initial reading HCI 1.2 ml 1.8 ml Volume of…

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Q: Method A: Dilute 10.00 mL up to 100 mL with a transfer pipet and volumetric flask. Then take 10.00…

A: The absolute uncertainty will be 0.1125

Q: Trial #1 Trial #2 Trail #3 Trial #4 Volume Vinegar (mL) 2.00 2.00 2.00 2.00 Click or tap here to…

A: The burette is filled with NaOH solution. To take reading of NaOH solution we take the lower…

Q: Estimate Trial 1 Trial 2 Trial 3 Mass of oxalic acid 0.2237g dihydrate (g) 0.2360g 0.2166g 0.2467g…

A: The volume of NaOH added = Final NaOH burette reading - Initial NaOH burette reading Moles of oxalic…

Q: Trials 1 2 3 Volume of aliquot of standard CaCO, solution 25.00 (ml) 25.00 25.00 Volume of titrant,…

A: Titer for trial 1 is determined as shown below.

Q: Data & Results: 0.12M Molarity of the standardized NaOH from the previous lab: Trial 1 Trial 2 Trial…

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Q: Initial burette reading (mL) 2.29   1.41   1.95   Molarity of NaOH (M) 0.100   0.100   0.100…

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Q: Trial 1 Trial 2 Trial 3 Volume of sample 10mL 10mL 10mL Volume of added 90mL 90mL 90mL distilled…

A: % of lead in water calculated as followed.

Ionic Equilibrium

Chemical equilibrium and ionic equilibrium are two major concepts in chemistry. Ionic equilibrium deals with the equilibrium involved in an ionization process while chemical equilibrium deals with the equilibrium during a chemical change. Ionic equilibrium is established between the ions and unionized species in a system. Understanding the concept of ionic equilibrium is very important to answer the questions related to certain chemical reactions in chemistry.

Arrhenius Acid

Arrhenius acid act as a good electrolyte as it dissociates to its respective ions in the aqueous solutions. Keeping it similar to the general acid properties, Arrhenius acid also neutralizes bases and turns litmus paper into red. 

Bronsted Lowry Base In Inorganic Chemistry

Bronsted-Lowry base in inorganic chemistry is any chemical substance that can accept a proton from the other chemical substance it is reacting with.