Trials 1 2 3 Volume of aliquot of standard CaCO, solution 25.00 (ml) 25.00 25.00 Volume of titrant, EDTA (ml) 23.20 23.50 23.34 Titer (mg CaCO,/mL EDTA) Trial 1 Trial 2 Trial 3
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Q: Standardization of EDTA Solution Weight of pure CaCO3: 0.2517 g % Purity of CaCO3: 98.0% Total…
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- Standardization of EDTA Solution Weight of pure CaCO3: 0.2517 g % Purity of CaCO3: 98.0% Total volume of standard CaCO3 solution: 250.00 mL Trial 1 2 3 Volume of standard CaCO3 solution (ml) 25.00 25.00 25.00 Final Volume Reading EDTA (ml) 24.30 47.95 24.72 Initial Volume Reading EDTA (ml) 0.00 24.30 0.20 Volume of titrant, EDTA (ml) Molarity of EDTA (M)Standardization of EDTA Solution Weight of pure CaCO3: 0.2514 g % Purity of CaCO3: 98.0% Total volume of standard CaCO3 solution: 250.00 mL Using the information given in the table, show a step-by-step process to compute the missing values. Take note of the % purity and total volume. Trial 1 2 3 Volume of standard CaCO3 solution (ml) 25.00 25.00 25.00 Final Volume Reading EDTA (ml) 24.30 47.95 24.72 Initial Volume Reading EDTA (ml) 0.00 24.30 0.20 Volume of titrant, EDTA (ml) Molarity of EDTA (M)Density of solution:Trial 1: 1.2 g/mLTrial 2: 1.2 g/mLTrial 3: 1.2 g/mL Average density = 1.2 g/mL What is the relative average deviaion, %?
- Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 2.29 1.41 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 50.37 49.39 49.84 Table 2. Titration data Trial 1 Trial 2 Trial 3 Initial burette reading (mL) 2.29 1.41 1.95 Molarity of NaOH (M) 0.100 0.100 0.100 Volume of vinegar sample (mL) 5.00 5.00 5.00 Final burette reading (mL) 50.37 49.39 49.84 Expected color at end point Volume of NaOH used (mL) 48.08 47.98 47.89 Compute for the ff: a. Average moles of acetic acid (mol)? b. Average molarity of acetic acid (M)? c. Average molarity of acetic acid (M)?A 50.00 (±0.03) mL portion of an HCl solution required 29.71(±0.03) mL of 0.01963(±0.0030) M Ba(OH)2 to reach an end point with bromocresol green indicator. The molar concentration of the HCl is calculated using the equation below (attached image): a.) Calculate the uncertainty of the result (absolute error). M=0.02333(±?????) M b.) Calculate the coefficient of variation for the result. CV= (Sy/y) x 100%Felodipine calcium channel blocker standard (0.251mg/ml) and felodipine sample (0.245mg/ml) solutions were prepared and injected to the HPLC. The peak area of felodipine standard is 275428 and the sample is 272982. The potency (purity) of felodipine standard is 98.9%. What is the assay percentage of felodipine? a. 102.23 b. 98.71 c. 101.07 d. 100.42
- The internal standard method compensates for errors that affect both the analyte and the reference. True False20.0 mL water sample was titrated with 0.0100 M EDTA solution that required 14.50 mL for CaCO3 hardness. The total hardness of the water sample in terms of CaCO3 (MW = 100.1 g/mole) in parts per million is _________? Note: Express final answer using least number of significant figures. 2. If 35.2 mL of EDTA solution is required to reach the endpoint with 0.3120-g of primary standard grade CaCO3 (MW = 100.1 g/mole), the normal concentration of the EDTA (MW = 292.24) solution is _________ N?FT-IR technique can be utilized for the analysis of unknown analytes by matching it with__________. Both choices are correct Commercial library/database Reference standard
- Which sentence is false about gravimetric analysis? a. It is used for inorganic b. It is used to assay barium c. It is used to assay of d. Relative precision 3% to 4%I got a task in analytical chemistry to calibrate, standardize, verify and validate an analytical balancesA volume of 250 ml of a 0.05 M solution of a reagent of formula weight (relative molecular mass) 40 was made up, the weighing being done by difference. The standard deviation of each weighing was 0.0001 g. The standard deviation of the volume of solvent used was 0.05 ml. Express this as a relative standard deviation. Hence calculate the relative standard deviation of the molarity of the solution.