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- Please answer fast it’s very important and urgent I say very urgent so please answer super super fast please For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466Downvoted for wrong solution. A river is carrying water containing 2000 mg/l Magnesium Chloride into a small lake. The lake has a naturally occurring Magnesium Chloride of 50 mg/l. If the river flow is 2500 Lmin and the lake flow rate is 1.5 m³.sec¹, what is the concentration of MgCl2 in the lake after the discharge point? Assume that the flows in the river and lake are completely mixed, that the salt is a conservative substance, and the system is at steady state.Please answer super fast and answer all questions and show calculations For the image attached For 1. a Mass of metal: Trial 1 is 35.0228 g Trial 2 is 35.0915 g Trial 3 is 34.0821 g Mass of water: Trial 1 is 20.0177 g Trial 2 is 20.0250 g Trial 3 is 20.0168 g For delta t of water: Trial 1 is 15.5 C Trial 2 is 15.7 C Trial 3 is 15.1 C For delta t of metal Trial 1 is 80.1 C Trial 2 is 80.2 C Trial 3 is 79.5 C For B my calculated Specific heat is: Trial 1 is 0.462 Trial 2 is 0.467 Trial 3 is 0.466
- If 35,000 kg of whole milk containing 4% fat is to be separated in a 6-hour period into skim milk with 0.45% fat and cream with 45% fat, what are the mass flow rates of the two output streams from a continuous centrifuge which accomplishes this separation? (Ans; Cream=464.8335kg/h, Skim milk= 5368.4998kg/h)1. Estimate the density of a 25-API gravity dead oil at 100 F.calculate the flow rate in ml/hr . order 40meq/l at 10meq/hr in 1000ml in d5w supply 20meq/10ml
- can you answer, please? the experimental data are Reference: https://www.youtube.com/watch?v=OOXRkycKEOc&feature=youtu.be and https://www.youtube.com/watch?v=3wLJLm0QLpg&feature=youtu.beExpress 20,000ppb as a percentage strength A. 2% B. 0.02% C. 0.00002% D. 0.002%Chemistry The levels of an organic pollutant (P) in the groundwater at the perimeter of a plant were a cause for concern. A 10 mL sample of the water was taken and the pollutant was extracted with 95% efficiency using 25 mL of diethyl ether. GC was used to analyse the concentration of P in diethyl ether. A calibration curve was plotted for a series of standards of P which yielded the following results: Peak Area Toluene Conc. (µg/ml) 12,000 2.6 23,700 5.0 35,500 7.7 46,800 9.9 31,250 Sample Determine the concentration of P in ppb in the initial groundwater sample.
- 4. Ksp=4.1x10-36 for Pb3(AsO4)2Calculate Eofor Pb3(AsO4)2(s) + 6e- 3Pb(s) + 2AsO43-Pb2+ +2e- Pb(s) Eo= -0.126 VCALCULATE Vmax and KM values of the reaction as shown below ON LB PLOT Please don't provide handwriting solutionThere's 1 drink (and you are asked to determine the glucose concentration in the drink in the units of g/100mL. (Why these units? Well, once you have the concentrations in g/100mL you will be able to compare your values with the nutritional values given on the drink bottles’ labels). The sample of the drink was diluted 1/100 (i.e. by a factor of 100). This was an essential step in the method because, without it, the machine used to analyse the glucose concentration (spectrophotometer) would have given an error as the concentration would have been too high for accurate detection. What this means for you is that the dilution factor will need to be taken into consideration in your calculations (remember the aim is to calculate the concentration in the original drink and not in the diluted drink). You measured the concentration of their diluted drink using the spectrophotometer and their results were provided to them in the units mM (millimolar). Glucose Concentration in mM of drink =…