Write a recursive function named count_non_digits (word) which takes a string as a parameter and returns the number of non-digits in the parameter string. The function should return 0 if the parameter string contains only digits. Note: you may not use loops of any kind. You must use recursion to solve this problem. You can assume that the parameter string is not empty. For example: Test Result print(count_non_digits('123')) print(count_non_digits('2rPTy5')) print(count_non_digits('hello world')) 11 Answer: (penalty regime: 0, 0, 5, 10, 15, 20, 25, 30, 35, 40, 45, 50 %) Precheck Check

Using recursion, write a function sum that takes a single argument n and computes the sum of all integers between 0 and n inclusive. Do not write this function using a while or for loop. Assume n is non-negative. def sum(n): """Using recursion, computes the sum of all integers between 1 and n, inclusive. Assume n is positive. >>> sum(1) 1 >>> sum(5) # 1 + 2 + 3+ 4+ 5 15 "*** YOUR CODE HERE ***"

in the C++ version please suppose to have a score corresponding with probabilities at the end and do not use the count[] function. Please explain the detail when coding. DO NOT USE ARRAY. The game of Pig The game of Pig is a dice game with simple rules: Two players race to reach 100 points. Each turn, a player repeatedly rolls a die until either a 1 ("pig") is rolled or the player holds and scores the sum of the rolls (i.e. the turn total). At any time during a player's turn, the player is faced with two decisions: roll - if the player rolls 1: the player scores nothing and it becomes the opponents turn. 2 - 6: the number is added to the player's turn total and the player's turn continues. hold - The turn total is added to the player's score and it becomes the opponent's turn. This game is a game of probability. Players can use their knowledge of probabilities to make an educated game decision.   Assignment specifications Hold-at-20 means that the player will choose to roll…

No hand written and fast answer with explanation

Python: How do I create a recursive function asterisk with both recursive and base cases?   so for n=3, you would have below; *** ** *   code that I have:   for i in range(n): print("*",end="")

The following requirments that weren't mentioned for solving the following Python Code below: The provided code for alphabet, test_dups, test_miss, and histogram.  Your implementation of the has_duplicates function.  A loop that outputs duplicate information for each string in test_dups.  Your implementation of the missing_letters function.  A loop that outputs missing letters for each string in test_miss.  Write a function called missing_letters that takes a string parameter and returns a new string with all the letters of the alphabet that are not in the argument string. The letters in the returned string should be in alphabetical order.  Your implementation should use a histogram from the histogram function. It should also use the global variable alphabet. It should use this global variable directly, not through an argument or a local copy. It should loop over the letters in alphabet to determine which are missing from the input parameter.  The function missing_letters should…

Can this python code be done without using the isdigit() function. Please try to change the following code in the picture so it doesn't use isdigit().

Write code to complete raise_to_power(). Note: This example is for practicing recursion; a non-recursive function, or using the built-in function math.pow(), would be more common.Sample output with inputs: 4 24^2 = 16 def raise_to_power(base_val, exponent_val):   if exponent_val == 0:      result_val = 1   else:      result_val = base_val * ''' Your solution goes here '''    return result_val user_base = int(input())user_exponent = int(input()) print('{}^{} = {}'.format(user_base, user_exponent,      raise_to_power(user_base, user_exponent)))

Computer scientists and mathematicians often use numbering systems other than base 10. Write a program that allows a user to enter a number and a base and then prints out the digits of the number in the new base. Use a recursive function baseConversion (num, base) to print the digits. Hint: Consider base 10. To get the rightmost digit of a base 10 number, simply look at the remainder after dividing by 10. For example, 153 % 10 is 3. To get the remaining digits, you repeat the process on 15, which is just 153 // 10. This same process works for any base. The only problem is that we get the digits in reverse order (right to left). The base case for the recursion occurs when num is less than base and the output is simply num. In the general case, the function (recursively) prints the digits of num // base and then prints num % base. You should put a space between successive outputs, since bases greater than 10 will print out with multi-character "digits." For example, baseConversion(1234,…

Need help Writing a function, countVowels, that accepts a string as an argument. countVowels should return the number of vowels in that string. Use recursion.     example  countVowels('Four score and seven years'); // => 9