Chapter 0, Problem 42PO

To determine

The percent of the saline in the solution.

Answer to Problem 42PO

  $16\%$

Explanation of Solution

Given:

Amount of pure water $y=150$ milliliters Amount of saline $x=24$ milliliters

Formula used:

  $x$ is percent of $y$

  $=\frac{x\times 100}{y}\%$

Where,

  $x$ and $y$ are integers.

Calculation:

Percent of saline in pure water $=\frac{24\times 100}{150}$

  $\begin{array}{l}=\frac{240}{15}\\ =16\%\end{array}$

Conclusion:

Hence, the percent of the saline in the solution is 16%.