Chapter 0.4, Problem 19E

To determine

To calculate: The simplified form of $\frac{1}{3}-\frac{2}{9}$ .

Answer to Problem 19E

The simplified form of $\frac{1}{3}-\frac{2}{9}$ is $\frac{1}{9}$ .

Explanation of Solution

Given information:

The statement “ $\frac{1}{3}-\frac{2}{9}$ .”

Formula used:

When two or more fractions with different denominators are added or subtracted then firstly they are converted into fractions with same denominators and then accordingly added or subtracted.

Consider the provided statement “ $\frac{1}{3}-\frac{2}{9}$ .”

Recall that when two fractions having different denominator are subtracted then firstly they are converted into fractions with same denominators and then subtracted.

So, multiply $\frac{1}{3}$ by 3 in both numerator and denominator,

  $\frac{1\times 3}{3\times 3}=\frac{3}{9}$

Now, the given expression can be simplified as,

  $\begin{array}{c}\frac{1}{3}-\frac{2}{9}=\frac{3}{9}-\frac{2}{9}\\ \frac{1}{3}-\frac{2}{9}=\frac{3-2}{9}\\ \frac{1}{3}-\frac{2}{9}=\frac{1}{9}\end{array}$

Since, $\frac{1}{9}$ cannot be simplified further,

Hence, the simplified form of $\frac{1}{3}-\frac{2}{9}$ is $\frac{1}{9}$ .