Chapter 0.10, Problem 15E

To determine

The surface area of the box.

Answer to Problem 15E

The surface area of the boxis $\text{A=77}{\text{.3ft}}^{\text{2}}$

Explanation of Solution

Given :

l = 34in

w = 33.25 in

h = 66 in

Calculation:

Surface area of the box,

Surface area of rectangular prism:

  $\begin{array}{l}\text{A=2}\left[\text{wl+hl+hw}\right]\\ \text{here,}\\ \text{A=Surface}\text{area}\\ \text{h}\text{=}\text{height}\\ \text{w=}\text{width}\\ \text{l=}\text{length}\end{array}$

So,

Surface area of rectangular prism:

  $\begin{array}{l}\text{A=2}\left[\text{wl+hl+hw}\right]\\ \text{A=2}\left[\text{1130}\text{.5+2244+2194}\text{.5}\right]\\ \text{A=2}\left[\text{5569}\right]\\ {\text{A=11138in}}^{\text{2}}\\ \text{A=}\frac{\text{11138}}{\text{144}}{\text{ft}}^{\text{2}}\\ \text{A=77}{\text{.34ft}}^{\text{2}}\\ \text{A=77}{\text{.3ft}}^{\text{2}}\end{array}$

Therefore, the surface area of the box is $\text{A=77}{\text{.3ft}}^{\text{2}}$ .