Chapter 0, Problem 60POT

To determine

To find: the probability of greenor redmarblein the given conditions.

Answer to Problem 60POT

  $P\left(\text{green}\text{or}\text{red}\right)=\frac{7}{15}$ .

Explanation of Solution

Given:

The given condition is:

One marble is randomly selected from 3 red, 4 green, 2 black, and 6 blue marbles.

Concept used:

Probability of the events is given by

  $P\left(E\right)=\frac{\text{Number of possible outcomes}}{\text{Total number of possible outcomes}}$

Calculation:

According to the question, total number of outcomes is $3+4+2+6=15\text{marbles}$ .

number of redmarbles is 3 pencil and number of greenmarbles is 4 marbles.

Therefore, the probability of greenor red marbleis $P\left(\text{green}\text{or}\text{red}\right)=\frac{4+3}{\text{15}}=\frac{7}{15}$

Hence, the probability of green marbleis $P\left(\text{green}\text{or}\text{red}\right)=\frac{7}{15}$ .