Chapter 0, Problem 69POT

To determine

To find: the probability of odds of a value less than $0.25 of the given conditions. Write its simplest form.

Answer to Problem 69POT

  $P\left(\text{odds of value less than 0}\text{.25}\right)=6:19$ .

Explanation of Solution

Given:

The given condition is “a value less than

  $\$0.25$ ”.

Calculation:

Total number of jars containing pennies, nickels, dimes, and quarters is $20+15+12+3=50$ .

Total number of odd outcomes “a value less than

  $\$0.25$ ”is $\frac{025}{100}=\frac{1}{4}$

As total number of possible outcomes is 50Therefore, the ratio is $10:40$ .

Also, the value is less than $40 then the unfavorable outcomes is $20+15+3=38$

Therefore, favorable outcomes is $50-38=12$

Thus, the probability of odds of a value less than $0.25 is $P\left(\text{odds of value less than 0}\text{.25}\right)=\frac{12}{38}=\frac{6}{19}=6:19$ .

Hence, the probability of odds of a value less than $0.25 is $P\left(\text{odds of value less than 0}\text{.25}\right)=6:19$ .