Chapter 0, Problem 64PRT

To determine

To find: the odds of a nickel or a quater of the given conditions. Write its simplest form.

Answer to Problem 64PRT

  $P\left(\text{odd of nickel or quarter}\right)=27:23$ .

Explanation of Solution

Given:

The given condition is:

One coin is randomly selected from a jar containing 20 pennies, 15 nickels, 3 dimes, and 12 quarters.

Calculation:

Total number of jars containing pennies, nickels, dimes, and quarters is $20+15+12+3=50$ .

Total number of odd outcomes (exclude nickel or quarter) is $20+3=23$

Therefore, the odds of a nickel or quarter is

  $P\left(\text{odd of nickel or quarter}\right)=\frac{27}{23}$

Hence, the simplest form of the odds of a dime is $P\left(\text{odd of nickel or quarter}\right)=27:23$ .