ANALYSIS+DESIGN OF LINEAR CIRCUITS(LL)
ANALYSIS+DESIGN OF LINEAR CIRCUITS(LL)
8th Edition
ISBN: 9781119235385
Author: Thomas
Publisher: WILEY
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Textbook Question
Chapter 1, Problem 1.1P

Given an electrical quantity described in terms of words, scientific notation, or decimal prefix notation, convert the quantity to an alternate description. See Exercise 1-1.

1-1 Express the following quantities to the nearest standard prefix using no more than three digits.

  1. 20,000 Hz
  2. 1025 W
  3. 0.333 × 10 8 s
  4. 33 × 10 12 F

a.

Expert Solution
Check Mark
To determine

To express: The given quantity in nearest standard prefix notation.

Answer to Problem 1.1P

Using standard prefix notation, the quantity becomes 20 MHz .

Explanation of Solution

Given:

The quantity is 20,000,000 Hz .

Calculation:

According to the standard prefix notation, mega (M) is used to denote 106 .

So, the given quantity can be expressed as

  20,000,000 Hz=20×106 Hz=20 MHz .

Conclusion:

Therefore, using standard prefix notation, the quantity becomes 20 MHz .

b.

Expert Solution
Check Mark
To determine

To express: The given quantity in nearest standard prefix notation.

Answer to Problem 1.1P

Using standard prefix notation, the quantity becomes 1.02 kW .

Explanation of Solution

Given:

The quantity is 1025 W .

Calculation:

According to the standard prefix notation, kilo (k) is used to denote 103 .

So, the given quantity can be expressed as

  1025 W=1.025×103 W=1.025 kW .

Since maximum three digits can be used, the nearest equivalent expression using standard prefix notation will be

  1025 W=1.02 kW

Conclusion:

Therefore, using standard prefix notation, the quantity becomes 1.02 kW .

c.

Expert Solution
Check Mark
To determine

To express: The given quantity in nearest standard prefix notation.

Answer to Problem 1.1P

Using standard prefix notation, the quantity becomes 3.33 ns .

Explanation of Solution

Given:

The quantity is 0.333×108 s .

Calculation:

According to the standard prefix notation, nano (n) is used to denote 109 .

So, the given quantity can be expressed as

  0.333×108 s=3.33×109 s=3.33 ns .

Conclusion:

Therefore, using standard prefix notation, the quantity becomes 3.33 ns .

d.

Expert Solution
Check Mark
To determine

To express: The given quantity in nearest standard prefix notation.

Answer to Problem 1.1P

Using standard prefix notation, the quantity becomes 33 pF .

Explanation of Solution

Given:

The quantity is 33×1012 F .

Calculation:

According to the standard prefix notation, pico (p) is used to denote 1012 .

So, the given quantity can be expressed as

  33×1012 F=33 pF .

Conclusion:

Therefore, using standard prefix notation, the quantity becomes 33 pF .

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ANALYSIS+DESIGN OF LINEAR CIRCUITS(LL)

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