Chemistry: The Molecular Nature of Matter and Change
Chemistry: The Molecular Nature of Matter and Change
8th Edition
ISBN: 9781259631757
Author: Martin Silberberg Dr., Patricia Amateis Professor
Publisher: McGraw-Hill Education
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Chapter 1, Problem 1.36P

(a)

Interpretation Introduction

Interpretation:

The volume of a bacterial cell in cubic millimeters (mm3) is to be calculated.

Concept introduction:

Volume is a physical quantity and its SI unit is cubic meter (m3). The volume of an object is equal to the product of the height, length, and breadth of the object. Length, breadth, and height of an object is measured in the units of length. Therefore, volume has the unit of length to the cubic power. The other unit of the volume are liter, milliliter, cubic decimeter, microliter.

The conversion of one unit into another can be done using a proper conversion factor. Conversion factors are the ratios that relate the two different units of a quantity. It is also known as dimensional analysis or factor label method.

In the unit conversion problems, the given information is multiplied by the conversion factors to obtain the desired information. The unit conversion can be done as follows:

(beginning unit)(Final unitbeginning unit)=Final unit

(a)

Expert Solution
Check Mark

Answer to Problem 1.36P

The volume of a bacterial cell in cubic millimeters (mm3) is 2.56×109 mm3/cell.

Explanation of Solution

The volume of a bacterial cell in cubic micrometer (μm3) is 2.56 μm3.

The road map to calculate the volume of a bacterial cell in cubic millimeters (mm3) is as follows:

Chemistry: The Molecular Nature of Matter and Change, Chapter 1, Problem 1.36P , additional homework tip  1

The conversion factor to convert volume from cubic micrometer (μm3) to cubic meter (m3) is,

(1 μm)3=(1×106 m)3

The conversion factor to convert volume from cubic meter (m3) to cubic millimeters (mm3)  is,

(1×103 m)3=(1 mm)3

Convert the volume from cubic micrometer (μm3)  to cubic millimeters (mm3) as:

Volume(mm3)=2.56 μm3((1×106 m)3(1 μm)3)((1 mm)3(1×103 m)3)=2.56×109 mm3/cell

Conclusion

The volume of a bacterial cell in cubic millimeters (mm3) is 2.56×109 mm3/cell.

(b)

Interpretation Introduction

Interpretation:

The volume of 105 bacterial cell in liter (L) is to be calculated.

Concept introduction:

Volume is a physical quantity and its SI unit is cubic meter (m3). The volume of an object is equal to the product of the height, length, and breadth of the object. Length, breadth, and height of an object is measured in the units of length. Therefore, volume has the unit of length to the cubic power. The other unit of the volume are liter, milliliter, cubic decimeter, microliter.

The conversion of one unit into another can be done using a proper conversion factor. Conversion factors are the ratios that relate the two different units of a quantity. It is also known as dimensional analysis or factor label method.

In the unit conversion problems, the given information is multiplied by the conversion factors to obtain the desired information. The unit conversion can be done as follows:

(beginning unit)(Final unitbeginning unit)=Final unit

(b)

Expert Solution
Check Mark

Answer to Problem 1.36P

The volume of 105 bacterial cell in liter (L) is 1010 L.

Explanation of Solution

The volume of a bacterial cell in cubic micrometer (μm3) is 2.56 μm3.

The road map to calculate the volume of 105 bacterial cell in liter (L) is as follows:

Chemistry: The Molecular Nature of Matter and Change, Chapter 1, Problem 1.36P , additional homework tip  2

The conversion factor to convert volume from cubic micrometer (μm3) to cubic meter (m3) is,

(1 μm)3=(1×106 m)3

The conversion factor to convert volume from cubic meter (m3) to cubic centimeters (cm3)  is,

(1×102 m)3=(1 cm)3

The conversion factor to convert volume from cubic centimeters (cm3) to milliliters (mL) is,

(1 cm)3=1 mL

The conversion factor to convert volume from milliliters (mL) to liter (L) is,

1 mL=103 L

Convert the volume from cubic micrometer (μm3) to liter (L) as:

Volume(L)=2.56 μm3((1×106 m)3(1 μm)3)((1 cm)3(1×102 m)3)(1 mL(1 cm)3)(103 L1 mL)=2.56×1015 L/cell

Calculate the volume of 105 bacterial cell in liter (L) as:

 Volume(L)=(105 cell)(2.56×1015 L/cell)=2.56×1010 L=1010 L

Conclusion

The volume of 105 bacterial cell in liter (L) is 1010 L.

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Chapter 1 Solutions

Chemistry: The Molecular Nature of Matter and Change

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