Modern Physics For Scientists And Engineers
2nd Edition
ISBN: 9781938787751
Author: Taylor, John R. (john Robert), Zafiratos, Chris D., Dubson, Michael Andrew
Publisher: University Science Books,
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Chapter 1, Problem 1.6P
To determine
To Estimate:
The final velocities of mass
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Consider a head-on, elastic collision between twobodies whose masses are m and M, with Itis well known that if m has speed and M is initiallyat rest, m will bounce straight back with its speedunchanged, while M will remain at rest (to anexcellent approximation). Use this fact to predict thefinal velocities if M approaches with speed and mis initially at rest.
Next up on this adventure, shooting bullets into conveniently shaped pendulum systems to have a setup for a ballistic pendulum. In this case, a projectile, (m = 0.50kg) is fired into a large block of wood of mass (m = 20 kg) suspended like a pendulum. As a result of this inelastic collision, the pendulum and projectile together swing up to a height of 10m. What was the initial speed of the bullet?
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After finding the angle Θ2 speed v2 for the larger mass, show that the collision is elastic.
Chapter 1 Solutions
Modern Physics For Scientists And Engineers
Ch. 1 - Prob. 1.1PCh. 1 - Prob. 1.2PCh. 1 - Prob. 1.3PCh. 1 - Prob. 1.4PCh. 1 - Prob. 1.5PCh. 1 - Prob. 1.6PCh. 1 - Prob. 1.7PCh. 1 - Prob. 1.8PCh. 1 - Prob. 1.9PCh. 1 - Prob. 1.10P
Ch. 1 - Prob. 1.11PCh. 1 - Prob. 1.12PCh. 1 - Prob. 1.13PCh. 1 - Prob. 1.14PCh. 1 - Prob. 1.15PCh. 1 - Prob. 1.16PCh. 1 - Prob. 1.17PCh. 1 - Prob. 1.18PCh. 1 - Prob. 1.19PCh. 1 - Prob. 1.20PCh. 1 - Prob. 1.21PCh. 1 - Prob. 1.22PCh. 1 - Prob. 1.23PCh. 1 - Prob. 1.24PCh. 1 - Prob. 1.25PCh. 1 - Prob. 1.26PCh. 1 - Prob. 1.27PCh. 1 - Prob. 1.28PCh. 1 - Prob. 1.29PCh. 1 - Prob. 1.30PCh. 1 - Prob. 1.31PCh. 1 - Prob. 1.32PCh. 1 - Prob. 1.33PCh. 1 - Prob. 1.34PCh. 1 - Prob. 1.35PCh. 1 - Prob. 1.36PCh. 1 - Prob. 1.37PCh. 1 - Prob. 1.38PCh. 1 - Prob. 1.39PCh. 1 - Prob. 1.40PCh. 1 - Prob. 1.41PCh. 1 - Prob. 1.42PCh. 1 - Prob. 1.43PCh. 1 - Prob. 1.44PCh. 1 - Prob. 1.45PCh. 1 - Prob. 1.46PCh. 1 - Prob. 1.47PCh. 1 - Prob. 1.48PCh. 1 - Prob. 1.49PCh. 1 - Prob. 1.50PCh. 1 - Prob. 1.51PCh. 1 - Prob. 1.52PCh. 1 - Prob. 1.53P
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- In an elastic collision of two particles with masses m1 and m2, the initial velocities are u1 and u2 = u1. If the initial kinetic energies of the two particles are equal, find the conditions on u1/u2 and m1/m2 such that m1 is at rest after the collision. Examine both cases for the sign of .arrow_forwardTwo manned satellites approaching one another at a relative speed of 0.150M/S intend to dock. The first has a mass of 3.00×10^3 kg, the second a mass of 7.50 x 10^3 kg . Assume that the positive direction is directed from the second satellite towards the first satellite. (a) Calculate the final velocity after docking, in the frame of reference in which the first set a lot was originally at rest. m/s ? (b) what is the loss of kinetic energy in this inelastic collision? j ? (c) repeat both parts in the frame of reference in which the second satellite was originally at rest. Final velocity m/s ? loss of kinetic energy j ? explain why the change in velocity is different in the two frames, where areas the change in kinetic energy is the same in both. I used ^ to show exponentsarrow_forwardIn an experiment, a particle of mass m is shot with speed v0 against a second resting particle of mass 2m After impact, three particles are observed, where the sketched directions and the following masses and velocities are detected during measurements: m1 = m, v1 = 2v0, v2 = v0/2. Determine m2, m3 and v3.arrow_forward
- An object A moving with velocity v collides with a stationary object B. After the collision, A is moving with velocity 2 1 v and B with velocity 3 2 v. Find the ratio of their masses. If, instead of bouncing apart, the two bodies stuck together after the collision, with what velocity would they then move?arrow_forwardShow solution A particle A, of mass 8 kg, collides with a particle B, of mass m2 kg. The velocity of particle A before the collision was 5 m/s and the velocity of particle B before the collision was 2.2 m/s. Given the velocity of particle A after the collision was -4 m/s, and the velocity of particle B was 3 m/s, what was the mass of particle B?arrow_forwardProve that the linear momentum of a system of particles is conserved.arrow_forward
- How much kinetic energy is lost in the inelastic collisions? Where does it go? Is it still in the “closed system” or has it been lost to surroundings?arrow_forwardStarting from Newton’s second law of motion, prove that impulse imparted on an object is equal to the change in momentum its momentum. Two masses m1 and m2 with a separation distance of d, attract each with a force F. What is the relationship between the F, m1, m2, and d? By what factor will the force of attraction change if the distance is quadrupled? A 400 kg object moving at a speed of 5 m/s to the right collides with a 600 moving at 2 m/s to the left. After the collision, the 600 kg object moves to the right at a speed of 3 m/s. Determine, the velocity of the 400 kg object after the collisionarrow_forwardProve that the kinetic energy of an object of mass m and momentum p can be expressed as:arrow_forward
- A particle of mass m moving along the x-axis with a velocity component +u collides head-on and sticks to a particle of mass m/3 moving along the x-axis with the velocity component −u. What is the mass M of the resulting particle?arrow_forwardCheck Your Understanding What happens to force and accleration as the vehicles fall together? What wil our estimate of the velocity at a collision higher or lower than the speed actually be? And finally, what would happen if the masses were not identical? Would the force on each be the same or different? How about their accelerations?arrow_forward(a) What is the momentum of a 2000-kg satellite orbiting at 4.00 km/s? (b) Find the ratio of this momentum to the classical momentum. (Hint: Use the approximation that at low velocities.)arrow_forward
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Elastic and Inelastic Collisions; Author: Professor Dave Explains;https://www.youtube.com/watch?v=M2xnGcaaAi4;License: Standard YouTube License, CC-BY