Chemistry: An Atoms-Focused Approach
1st Edition
ISBN: 9780393124200
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster
Publisher: W. W. Norton & Company
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A cup of sea water from Galveston Bay ( containing 3.0 x 104 ppm NaCl. Density for sea water is 1.05 g/mL ) and a cup of soy sauce ( containing 0.8 % ( wt% ) NaCl. Density for soy sauce is 1.1 g/mL ). which one tastes more salty ? Assume Na element is the only contributor for the salty taste. ( Given NaCl : 58.5 g/mol ), and which one has more salinity
Q5. As part of the aspirin synthesis lab, the orgo students also had to perform the following calculation to demonstrate their knowledge. Are you able to help them work this out?
Saponification is a process in which soap is produced from the chemical reaction between animal fat (triglycerides) and a strong base such as KOH.
An example of such a balanced chemical reaction is shown here:
C51H98O6 + 3KOH à C3H5(OH)3 + 3C16H31O2K
Triglyceride Soap
If, during the saponification reaction, 231.5 g of C51H98O6 is mixed with 231.5 g of KOH and 160 g of soap is produced:
Calculate the theoretical yield of soap (in grams), C16H31O2K, and indicate which species is the limiting reactant. Provide your answer to 2 decimal places (5).
Calculate the percent yield for this reaction. Provide your answer to 1 decimal place (1).
Show ALL steps and equations involved in your calculations. Remember to label all steps clearly and use appropriate units.
Compare sugar (C12H22O11) to Carbon (C) , Hydrogen (H) and Oxygen(O)
1) What are the similarities of sugar and C, H,O to atoms and molecules?
2) What are the differences of sugar and C, H, O as to atoms and molecules?
3) Can you find sugar on the Periodic Table? why or why not
4) Can you find C, H, O on the Periodic Table? why or why not
Chapter 1 Solutions
Chemistry: An Atoms-Focused Approach
Ch. 1 - Prob. 1.1VPCh. 1 - Prob. 1.2VPCh. 1 - Prob. 1.3VPCh. 1 - Prob. 1.4VPCh. 1 - Prob. 1.5VPCh. 1 - Prob. 1.6VPCh. 1 - Prob. 1.7QACh. 1 - Prob. 1.8QACh. 1 - Prob. 1.9QACh. 1 - Prob. 1.10QA
Ch. 1 - Prob. 1.11QACh. 1 - Prob. 1.12QACh. 1 - Prob. 1.13QACh. 1 - Prob. 1.14QACh. 1 - Prob. 1.15QACh. 1 - Prob. 1.16QACh. 1 - Prob. 1.17QACh. 1 - Prob. 1.18QACh. 1 - Prob. 1.19QACh. 1 - Prob. 1.20QACh. 1 - Prob. 1.21QACh. 1 - Prob. 1.23QACh. 1 - Prob. 1.24QACh. 1 - Prob. 1.25QACh. 1 - Prob. 1.26QACh. 1 - Prob. 1.27QACh. 1 - Prob. 1.28QACh. 1 - Prob. 1.29QACh. 1 - Prob. 1.30QACh. 1 - Prob. 1.31QACh. 1 - Prob. 1.32QACh. 1 - Prob. 1.33QACh. 1 - Prob. 1.34QACh. 1 - Prob. 1.35QACh. 1 - Prob. 1.36QACh. 1 - Prob. 1.37QACh. 1 - Prob. 1.38QACh. 1 - Prob. 1.39QACh. 1 - Prob. 1.40QACh. 1 - Prob. 1.41QACh. 1 - Prob. 1.42QACh. 1 - Prob. 1.43QACh. 1 - Prob. 1.44QACh. 1 - Prob. 1.45QACh. 1 - Prob. 1.46QACh. 1 - Prob. 1.47QACh. 1 - Prob. 1.48QACh. 1 - Prob. 1.49QACh. 1 - Prob. 1.50QACh. 1 - Prob. 1.51QACh. 1 - Prob. 1.52QACh. 1 - Prob. 1.53QACh. 1 - Prob. 1.54QACh. 1 - Prob. 1.55QACh. 1 - Prob. 1.56QACh. 1 - Prob. 1.57QACh. 1 - Prob. 1.58QACh. 1 - Prob. 1.59QACh. 1 - Prob. 1.60QACh. 1 - Prob. 1.61QACh. 1 - Prob. 1.62QACh. 1 - Prob. 1.63QACh. 1 - Prob. 1.64QACh. 1 - Prob. 1.65QACh. 1 - Prob. 1.66QACh. 1 - Prob. 1.67QACh. 1 - Prob. 1.68QACh. 1 - Prob. 1.69QACh. 1 - Prob. 1.70QACh. 1 - Prob. 1.71QACh. 1 - Prob. 1.72QACh. 1 - Prob. 1.73QACh. 1 - Prob. 1.74QACh. 1 - Prob. 1.75QACh. 1 - Prob. 1.76QACh. 1 - Prob. 1.77QACh. 1 - Prob. 1.78QACh. 1 - Prob. 1.79QACh. 1 - Prob. 1.80QACh. 1 - Prob. 1.81QACh. 1 - Prob. 1.82QACh. 1 - Prob. 1.83QACh. 1 - Prob. 1.84QACh. 1 - Prob. 1.85QACh. 1 - Prob. 1.86QACh. 1 - Prob. 1.87QACh. 1 - Prob. 1.88QACh. 1 - Prob. 1.90QACh. 1 - Prob. 1.91QACh. 1 - Prob. 1.92QACh. 1 - Prob. 1.93QACh. 1 - Prob. 1.94QA
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- 2.97 LDPE has a density in the range of 0.915—0.935 g/cm3, and HDPF has a density in the range of 0.940—0.965 g/cm3. You receive a small disk, 2.0 cm high with a 6.0-cm diameter, from a manufacturer of polyethylene, but its label is missing. You measure the mass of the disk and find that it is 53.8 g. Is the material HDPE or LDPE?arrow_forwardQ5. As part of the aspirin synthesis lab, the orgo students also had to perform the following calculation to demonstrate their knowledge. Are you able to help them work this out?Saponification is a process in which soap is produced from the chemical reaction between animal fat (triglycerides) and a strong base such as NaOH. An example of such a balanced chemical reaction is shown here:C57H110O6 + 3NaOH à C3H5(OH)3 + 3C18H35O2NaIf, during the saponification reaction, 228.5 g of C57H110O6 is mixed with 211.7 g of NaOH and 180 g of soap is produced: a. Calculate the theoretical yield of soap (in grams), C18H35O2Na, and indicate which species is the limiting reactant. Provide your answer to 2 decimal places. b. Calculate the percent yield for this reaction. Provide your answer to 1 decimal place. Show ALL steps and equations involved in your calculations. Remember to label all steps clearly and use appropriate unitsarrow_forward6.8 g H2O Express your answer in molecules to two sinificant figuresarrow_forward
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