The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5 × 10 3 k m . s − 1 has to be calculated. Concept Introduction: Photoelectric effect : If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, E k = 1 2 m e v 2 . An equation which represents the kinetic energy is given below. E k = h ν − Φ Where, E k is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

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Answer 1

Question

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

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Answer 2

Question

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

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Answer 3

Question

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

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Answer 4

Question

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

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Answer 5

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

Answer 6

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

Answer 7

Chapter 1, Problem 1B.16E

Interpretation Introduction

Interpretation:

The wavelength of the radiation that must be used to eject electrons with a velocity of 1.5×103km.s−1 has to be calculated.

Concept Introduction:

Photoelectric effect:

If the energy of the photon is greater than work function, then an electron can be ejected with a kinetic energy, Ek=12mev2. An equation which represents the kinetic energy is given below.

Ek=hν−Φ

Where, Ek is the kinetic energy, h is the Planck’s constant, ν is the frequency of radiation and Φ is the work function.

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 1 - Prob. 1A.1AST Ch. 1 - Prob. 1A.1BST Ch. 1 - Prob. 1A.2AST Ch. 1 - Prob. 1A.2BST Ch. 1 - Prob. 1A.1E Ch. 1 - Prob. 1A.3E Ch. 1 - Prob. 1A.4E Ch. 1 - Prob. 1A.5E Ch. 1 - Prob. 1A.6E Ch. 1 - Prob. 1A.7E

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