Quantitative Chemical Analysis
Quantitative Chemical Analysis
9th Edition
ISBN: 9781464135385
Author: Daniel C. Harris
Publisher: W. H. Freeman
Question
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Chapter 1, Problem 1.CE

(a)

Interpretation Introduction

Interpretation:

Concentration of NO3 present in solution made of 12.6 ppm of dissolved Ca(NO3)2 has to be calculated in in ppm.

Concept introduction:

Parts Per Million refers to a term that expresses concentration of certain substance in a mixture of substances.   It is denoted as ppm.  It is represented as,

ppm = mass of substancemass of sample×106

In solution concentrations, 1 ppm is equivalent to 1 μg/mL or 1 mg/L.

Molarity is a concentration term that is used to express the concentration of the solute in solution.  It is represented as,

molarity = no.of moles of solutevolume of solution in L

(a)

Expert Solution
Check Mark

Answer to Problem 1.CE

Concentration of NO3 is calculated to be 9.52 ppm.

Explanation of Solution

Each mol of Ca(NO3)2 furnishes one mol Ca2+ ion and two mol NO3 ions.  Formula of NO3 62.005 .  So the mass of Nitrate ion in Ca(NO3)2 is,

2 mol NO31mol Ca(NO3)2×62.005 g NO3/mol NO3 164.88 g Ca(NO3)2/mol Ca(NO3)2=0.7558 g NO3/g Ca(NO3)2

Given that the solution made of 12.6 ppm of dissolved Ca(NO3)2 which implies the solution contains 12.6 μg of Ca(NO3)2 per mL of solution or 12.6 mg of Ca(NO3)2 per liter or per gram of the solution.  0.7558 g NO3 is present in per gram of Ca(NO3)2 .  Thus 1 μg Ca(NO3)2 contains 0.7558 μg NO3 and so 0.7558  ×12.6 ppm = 9.52 ppm of  NO3 ions present in solution.

(b)

Interpretation Introduction

Interpretation:

The number of ppm of Ca(NO3)2 in 0.144 mM Ca(NO3)2 has to be calculated.

Concept introduction:

Parts Per Million refers to a term that expresses concentration of certain substance in a mixture of substances.   It is denoted as ppm.  It is represented as,

ppm = mass of substancemass of sample×106

In solution concentrations, 1 ppm is equivalent to 1 μg/mL or 1 mg/L.

Molarity is a concentration term that is used to express the concentration of the solute in solution.  It is represented as,

molarity = no.of moles of solutevolume of solution in L

(b)

Expert Solution
Check Mark

Answer to Problem 1.CE

The number of ppm of Ca(NO3)2 in 0.144 mM Ca(NO3)2 is calculated to be 23.6 ppm.

Explanation of Solution

Given that concentration of Ca(NO3)2 in solution is 0.144 mM which is 0.144 ×103M .

As we know,

molarity = no.of moles of solutevolume of solution in L

No. of moles of the solute Ca(NO3)2 is,

no.of moles of Ca(NO3)2 = weight of Ca(NO3)2molecular weight of Ca(NO3)2

Therefore molarity of Ca(NO3)2 is,

molarity of Ca(NO3)2 = mass of Ca(NO3)2molar mass of Ca(NO3)2volume of solution in L

Formula weight of Ca(NO3)2 is 164.088

Let the volume of solution be 1 L and weight of Ca(NO3)2 required to make 0.144 ×103M solution be ‘x’.  then,

No. of moles of Ca(NO3)2 is,

molarity of Ca(NO3)2  =   x164.088 g/mol1 L0.144×103M =  x164.088 g/mol1 Lx =    0.144×103mol/L×164.088 g/mol =   23.6×103 g/L

As we know, 1 ppm = 1 mg/L ,

23.6×103 g/L =  23.6 ×103×103 mg/L = 23.6 mg/L = 23.6 ppm

(c)

Interpretation Introduction

Interpretation:

The number of ppm of NO3 in 0.144 mM Ca(NO3)2 has to be calculated.

Concept introduction:

Parts Per Million refers to a term that expresses concentration of certain substance in a mixture of substances.   It is denoted as ppm.  It is represented as,

ppm = mass of substancemass of sample×106

In solution concentrations, 1 ppm is equivalent to 1 μg/mL or 1 mg/L.

Molarity is a concentration term that is used to express the concentration of the solute in solution.  It is represented as,

molarity = no.of moles of solutevolume of solution in L

(c)

Expert Solution
Check Mark

Answer to Problem 1.CE

The number of ppm of NO3 in 0.144 mM Ca(NO3)2 is calculated to be 17.9 ppm.

Explanation of Solution

Given that concentration of Ca(NO3)2 in solution is 0.144 mM which is 0.144 ×103M . In previous step we found mass fraction of NO3 in Ca(NO3)2 is 0.7558 and 0.144 mM Ca(NO3)2 contains 23.6 ppm of Ca(NO3)2 .  Therefore ppm of NO3 in 0.144 mM Ca(NO3)2 is, 0.7558×23.6 ppm = 17.9 ppm

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