Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
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Chapter 1, Problem 27Q
To determine
If the radiusof the universe is larger than a hydrogen atom.
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Chapter 1 Solutions
Universe: Stars And Galaxies
Ch. 1 - Prob. 1QCh. 1 - Prob. 2QCh. 1 - Prob. 3QCh. 1 - Prob. 4QCh. 1 - Prob. 5QCh. 1 - Prob. 6QCh. 1 - Prob. 7QCh. 1 - Prob. 8QCh. 1 - Prob. 9QCh. 1 - Prob. 10Q
Ch. 1 - Prob. 11QCh. 1 - Prob. 12QCh. 1 - Prob. 13QCh. 1 - Prob. 14QCh. 1 - Prob. 15QCh. 1 - Prob. 16QCh. 1 - Prob. 17QCh. 1 - Prob. 18QCh. 1 - Prob. 19QCh. 1 - Prob. 20QCh. 1 - Prob. 21QCh. 1 - Prob. 22QCh. 1 - Prob. 23QCh. 1 - Prob. 24QCh. 1 - Prob. 25QCh. 1 - Prob. 26QCh. 1 - Prob. 27QCh. 1 - Prob. 28QCh. 1 - Prob. 29QCh. 1 - Prob. 30QCh. 1 - Prob. 31QCh. 1 - Prob. 32QCh. 1 - Prob. 33QCh. 1 - Prob. 34QCh. 1 - Prob. 35QCh. 1 - Prob. 36QCh. 1 - Prob. 37QCh. 1 - Prob. 38QCh. 1 - Prob. 39QCh. 1 - Prob. 40QCh. 1 - Prob. 41QCh. 1 - Prob. 42Q
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- A light-year (ly) is the distance light travels in one year (at speed of 2.998 ×× 108 m/sm/s ). An astronomical unit (AU) is the average distance from the Sun to Earth, 1.50 ×× 108 km. 1 year = 3.156 ×× 107 s. How many meters are there in 1.70 ly? Express your answer using three significant figures. Express in scientific notation! 1.70 ly = _________________m How many AU are there in 1.70 ly light-year? Express your answer using three significant figures. Express in scientific notation! 1.70 ly = _________________AUarrow_forwardIf the Sun's mass is about average, how many stars are there in the Milky Way galaxy? The mass of the Sun is of the order of 1030 kg and the mass of the Milky Way galaxy is of the order of 1042 kg.arrow_forwardIn astronomy, distances are often expressed in light-years. One light-year is the distance traveled by light in one year. If the distance to a star is 3.7 light-years, what is this distance in meters? (There are 365.25 days in one year.)arrow_forward
- What is the difference between the Solar System, the Galaxy, and the Universe?arrow_forwardWhy are light-years more convenient than miles, kilometers, or AU for measuring the distances to stars and galaxies?arrow_forwardThe distance from the Sun to the nearest star is about 4 1016 m. The Milky Way galaxy (Fig. P1.31) is roughly a disk of diameter 1021 in and thickness 1019 m. Find the order of magnitude of the number of stars in the Milky Way. Assume the distance between the Sun and our nearest neighbor is typical. Figure P1.31 The Milky Way galaxy.arrow_forward
- Assume the observable Universe is charge neutral, and that it contains n nuclei (hydrogen plus helium nuclei, ignoring other elements). Take the helium mass fraction as 1/4. How many electrons are there in the observable Universe? Enter your answer in scientific notation with one decimal place. Values: n = 1*10^80arrow_forwardAssume the observable Universe is charge neutral, and that it contains n nuclei (hydrogen plus helium nuclei, ignoring other elements). Take the helium mass fraction as 1/4. How many electrons are there in the observable Universe? Enter your answer in scientific notation with one decimal place. Value: n = 4*1080arrow_forwardAstronomers frequently say that “there are more stars in the universe than there are grains of sand on all the beaches on the earth”. Given that a typical grain of sand is about 0.5 – 1.0 mm in diameter, estimate the number of grains of sand on all the earth’s beaches. The diameter of the Earth is 12,742 km.arrow_forward
- Recent findings in astrophysics suggest that the observable universe can be modeled as a sphere of radius R=13.7x109 light-years=13.0 x 1025m with an average total mass density of about 1x10-26 kg/m3 Only about 4% of total mass is due to “ordinary” matter (such as protons, neutrons, and electrons). Estimate how much ordinary matter (in kg) there is in the observable universe. (For the light-year, see Problem 19.)arrow_forwardContra Parmenides and a previously universally accepted idea, at the end of his life, Stephen Hawking made the argument that a. the universe can and will create itself from nothing b. the cosmos is an illusion c. the cosmos does not exist d. Parmenides did not existarrow_forwardone hundred milli- (100 times one one-thousandth): 102 ✕ 10−3 = 10(2 + [−3]) = 10(2 − 3) = 10−1 = 0.1 (100 ÷ 1,000 = 0.1) one hundred micro- (100 times one one-millionth): 102 ✕ 10−6 = 10(2 + [−6]) = 10(2 − 6) = 10−4 How do we write one hundred nano- (100 times one-billionth)? 102 ✕ 10−9 = 10 We write ten micrometers as follows. 10 ✕ 10−6 m = 10−5 m How do we write ten nanoseconds? 10 ✕ 10−9 s = 10 sarrow_forward
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