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Concept explainers
(a)
Interpretation:
A balanced molecular equation for the preparation of lithium Sulfate (
Concept Introduction:
Acid and base reacts with each other and forms salts as product.
To give acid and base from the salt, salt is dissociated to ions. The positive metal ion formed is from base and negative ion formed is from acid.
For the positive metal ion,
(b)
Interpretation:
A balanced molecular equation for the preparation of sodium chloride (
Concept Introduction:
Acid and base reacts with each other and forms salts as product.
To give acid and base from the salt, salt is dissociated to ions. The positive metal ion formed is from base and negative ion formed is from acid.
For the positive metal ion,
(c)
Interpretation:
A balanced molecular equation for the preparation of potassium nitrate (
Concept Introduction:
Acid and base reacts with each other and forms salts as product.
To give acid and base from the salt, salt is dissociated to ions. The positive metal ion formed is from base and negative ion formed is from acid.
For the positive metal ion,
(d)
Interpretation:
A balanced molecular equation for the preparation of barium phosphate (
Concept Introduction:
Acid and base reacts with each other and forms salts as product.
To give acid and base from the salt, salt is dissociated to ions. The positive metal ion formed is from base and negative ion formed is from acid.
For the positive metal ion,
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Chapter 10 Solutions
EBK GENERAL, ORGANIC, AND BIOLOGICAL CH
- The main constituents in vinegar are water and ethanoic acid (CH3COOH). In order to determine the concentration of acid in homemade vinegar, a student titrated 25 cm3 of 001 M NaOH against the vinegar. The equation for the reaction is: CH3COOH(aq) + NaOH(aq) ® CH3COONa(aq) + H2O(l) The following titration results were obtained: Burette readings (cm3) Rough 1 2 Final burette reading 20.10 38.90 31.40 Initial burette reading 0.10 20.00 12.50 Volume of vinegar used 20.00 18.90 18.90 (a) What volume of vinegar should be used in the calculation? (b) What is the mole ratio of NaOH:CH3COOH? (c) Calculate the number of moles of alkali in 25 cm3 of NaOH solution used. (d) How many moles of acid were used in the titration? (e) Calculate the…arrow_forwardExamine the chemical reaction for the hydration of the salt calcium chloride, shown below: CaCl2(s)+H2O→Ca2++2Cl–CaCl2(s)+H2O→Ca2++2Cl–arrow_forwardTrans-oleic acid (18:1,D9) has a melting temperature of (44.5C) and cis-oleic acid (18:1,D9) has a melting point of (13.4C). Briefly explain the difference in melting points between the two.arrow_forward
- A patient’s treatment plan requires two IV solutions to be administered:20% magnesium sulfate, MgSO4, and 10% calcium chloride, CaCl2. Thenurse is concerned, MgSO4 and CaCl2 are listed as incompatible IVsolutions with the risk of solid precipitate formation (image shown toright). Write the chemical equation that predicts the products thatform when combining MgSO4 and CaCl2. Please use the providedsolubility chart to help you determine chemical phases.arrow_forwardThe formula for a sports rub cream is given in the literature as follows:Methylsalicylate 15 mLMenthol 10 gEucalyptus oil 1 gHydrophilic ointment, q.s. ad 100 g If the specific gravity of methyl salicylate is 1.18, how many grams of methylsalicylate would be needed to prepare two dozen 30-g tubes of ointment?arrow_forwardA base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 88 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont) Ni(OH), Zn(OH), Cu(OH), Hg(OH), Sn(OH), Cr(OH), A(OH), BaF, MgF, PbF, SrF, CaF, 2.4 x 10-5 X 10-8 x 10-8 1.9 x 10-12 1.6 x 10-16 4.5 X 10-17 1.6 x 10-19 3 2 x 10-16 4 Carbonates 7.9 x 10-10 3.9 x 10-11 X 10-26 NiCO, CaCO, BaCo, SrCO, CuCO, ZnCO, MnCO, 1.4 x 10-7 3 10-27 4.7 x 10- 6.7 x 5 x 6 x 10-38 2.5 x 10-43 Chlorides 10-31 1.6 x 10- 1.7 x 10-10 1.1 x 10-18 1.6 x 10-9 7 x 10-10 2.5 x 10-10 10-33 PBCI, AgCi Hg,Cl, Fe(OH), Co(OH), Sulfides 2 x 10-10 8.8 x 10-11 2.1 x 10-11 Bromides X 10-16 X 10-19 3 x 10-21 X 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 7. PbBr, AgBr Hg, Br, 4.6 x 10-6 5.0 x 10-13 Feco Ag,CO, CdCo, PBCO, MgCO, Hg,CO, Fes 4 8.2 x 10-12 5.2 x 10-12 1.5 x 10-15 1 x 10-15 NiS 1.3 x 10-22 Cos ZnS lodides Pbl, Agl…arrow_forward
- A base is added to a 0.050 M solution of MnCl2, raising the pH gradually. Calculate the pH of the solution when 70 of the manganese has precipitated? Table 5-7 Solubility-Product Constants, K, at 25°C Fluorides Chromates (cont.) Ag, Cro, PbCro, Hydroxides (cont.) Ni(OH), Zn(OH), Cu(OH), Hg(OH)2 Sn(OH), Cr(OH), Al(OH), Fe(OH), Co(OH), Sulfides Baf, MGF2 PbF, SrF, CaF, 2.4 x 10-6 1.9 x 10-12 1.6 x 10-16 8 x 10-8 X 10-8 7.9 x 10-10 3.9 x 10-11 2 x 10-16 4.5 X 10-17 4 1.6 x 10-19 X 10-26 X 10-27 6.7 x 10-31 Carbonates NiCO, CaCO, BaCO, SrCO, CuCO, ZnCO, MNCO, FeCo, Ag,CO, CdCo, PbCO, M9CO, Hg,CO, 1.4 X 10-7 4.7 x 10-9 3. Chlorides 1.6 x 10-9 PbCl, AgCI Hg,Cl, х 10-33 X 10-38 2.5 x 10-43 1.6 x 10-5 X 10-10 2.5 x 10-10 2 x 10-1o 8.8 x 10-11 2.1 X 10-11 7 1.7 x 10-10 1.1 X 10-18 6. Bromides PbBr2 X 10-16 X 10-19 X 10-21 5 x 10-22 2.5 x 10-22 X 10-26 1.0 x 10-28 MnS 4.6 x 10-6 5.0 x 10-13 Fes 4. AgBr Hg,Br, 8.2 x 10-12 NiS Cos Zns 1.3 x 10-22 3 5.2 x 10-12 1.5 x 10-15 1 x 10-15 9.0 x 10-15…arrow_forwardConsider a HCI solution with a pH of 4.70. a) Calculate the concentration of HCl. b) Identify the two underlying assumptions in part a). c) The original solution is diluted by 1,000 fold. Calculate the pH of the resulting solution. Make sure to indicate if the forementioned assumptions are still valid.arrow_forwardBenzalkonium chloride 17% w/v . . . . . qs Water qs . . . . . . . . . . . . . . . . . . . . . . 120 mL M. ft . solution such that 2 tbsp added to a pint of water will yield a 1:750 solution. How many milliliters of the 17% w/v stock solution will be needed to prepare the 120 mL? a 2.68 mL b 7.90 mL c 15.80 mL d 20.40 mL e 6.28 mLarrow_forward
- Consider these compounds: A. PbBr, B. MnS C. Ag,CO3 D. AIPO, Complete the following statements by entering the letter(s) corresponding to the correct compound(s). (If more than one compound fits the description, include all the relevant compounds by writing your answer as a string of characters without punctuation, e.g, ABC.) Without doing any calculations it is possible to determine that magnesium fluoride is more soluble than and magnesium fluoride is less soluble than| It is not possible to determine whether magnesium fluoride is more or less soluble than by simply comparing Kgp values.arrow_forwardConsider a buffer solution of acetate. The volume is 500 ml, the concentration is 200 mM, and the pH is 5.0. a. How many total moles of acetate plus acetic acid are present in the solution? Express answer as x.y with one digit before and one after the decimal place. b. What is the ratio of acetate ions (Ac-) to acetic acid ions (HAc) in the buffer solution (pH 5.0) if the pka is 4.76? Express the answer as x.yz with one digit before and two after the decimal place. c. How many moles of acetate are present in the solution? Express your answer to one decimal place. d. How many moles of acetic acid are present in the solution? Express your answer to one decimal place.arrow_forwardThe Ksp values of silver chromate Ag2CrO4 and silver iodate Ag(IO3) are given below. Ag2CrO4 Ag(IO3) Ksp 1.12 x 10-12 3.17 x 10-8 Based on these Ksp values, which of the following is true? Choose one option only. Options: a. In the solution consisting of 1.00 x10-4 M Ag+ and 5.00 x10-5 M CrO42-, Ag2CrO4 precipitate will form. b. In the solution consisting of 1.0 x10-4 M Ag+ and 1.0 x10-4 M IO3-, Ag(IO3) precipitate will form. c. In pure water, the solubility of Ag2CrO4 is lower than the solubility of Ag(IO3). d. In the solution consisting of 0.200 M CrO42- and 0.200 M IO3-, Ag2(CrO4) will precipitate first if we add Ag+ ions gradually into the above mixture.arrow_forward