General Chemistry
General Chemistry
7th Edition
ISBN: 9780073402758
Author: Chang, Raymond/ Goldsby
Publisher: McGraw-Hill College
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Chapter 10, Problem 10.70QP

(a)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(a)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of BeCl2 is 1800

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

BeCl2.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  1

BeCl2 is a triatomic molecule . Here the central atom beryllium atom does not have any lone pair of electrons whereas both terminal chlorine atoms have 3 pairs of electron. It is a AB2 type molecule. Since there are only two bonds, there is only one bond angle. Since there is no lone pair on the central atom, to minimize the repulsion, they form a linear geometry. So the bond angle between two atoms is 1800.

(b)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(b)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of BCl3 is 1200

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

BCl3.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  2

BCl3 contains four atoms. Here the central atom boron atom does not have any lone pair of electrons whereas the terminal chlorine atoms have 3 pairs of electron. It is a AB3 type molecule. Since there are only three bonds, there are  two bond angle. Since there is no lone pair on the central atom, to minimize the repulsion, they form a trigonal planar geometry. So the bond angle between two atoms is 1200.

(c)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(c)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of CCl4 is 109.50

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

CCl4.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  3

CCl4 contains five atoms. Here the central atom carbon atom does not have any lone pair of electrons whereas the terminal chlorine atoms have 3 pairs of electron. It is a AB4 type molecule. Since there is no lone pair on the central atom, to minimize the repulsion, they form a tetrahedral geometry. So the bond angle between two atoms is 109.50.

(d)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(d)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of CH3Cl is 109.50

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

CH3Cl.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  4

CH3Cl contains five atoms. Here the central atom carbon atom does not have any lone pair of electrons whereas the terminal chlorine atom has 3 pairs of electron. It is a AB4 type molecule. Since there is no lone pair on the central atom, to minimize the repulsion, they form a distorted tetrahedral geometry because of the size difference of terminal chlorine and hydrogen atoms. So the bond angle between two atoms is 109.50.

(e)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(e)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of Hg2Cl2 is 1800

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

Hg2Cl2.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  5

In the case of Hg2Cl2, both mercury atom does not have any lone pair of electrons whereas the terminal chlorine atoms have 3 pairs of electron. Both the mercury atom is of AB2 type molecule. . Since there is no lone pair on the central atom, to minimize the repulsion, they form a linear geometry. So the bond angle between two atoms is 1800.

(f)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(f)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of SnCl2 is 1200

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

SnCl2.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  6

In the case of SnCl2, the central atom tin atom have a lone pair of electron whereas the terminal chlorine atoms have 3 pairs of electron and is a AB2 with one lone pair of electron type molecule. There are only two bonds so there is only one bond angle. Since there is one lone pair on the central atom, to minimize the repulsion, they form a bent geometry. So the bond angle between two atoms is 1200.

 (g)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

 (g)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of H2O2 is 109.50

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

H2O2.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  7

In the case of H2O2, both oxygen atom have any two lone pair of electrons and is a AB2 with two lone pair of electron type molecule.. Since there is two lone pair on each oxygen atom, to minimize the repulsion, they form a tetrahedral geometry. So the bond angle between two atoms is 109.50.

(h)

Interpretation Introduction

Interpretation: The bond angle of the given molecule should be found.

Concept Introduction:

  • Bond angle measured that made between two nearby bonds. The angles between two adjacent bonds are known as bond angle.
  • Using VSEPR theory and Lewis structure, the exact geometry of a molecule can be obtained.
  • In VSEPR, the geometry of the molecule is explained based on minimizing electrostatic repulsion between the molecules’ valence electrons around a central atom
  • Lewis structures is also known as Lewis dot structures which represents the bonding between atoms of a molecule and the lone pairs of electrons that may exist in the molecule.

(h)

Expert Solution
Check Mark

Answer to Problem 10.70QP

The bond angle of SnH4 is 109.50

Explanation of Solution

To find: The bond angle of the given molecule

Given molecule is

SnH4.

Lewis structure of the given molecule is drawn below.

General Chemistry, Chapter 10, Problem 10.70QP , additional homework tip  8

SnH4 Contains five atoms. Here the central atom tin atom does not have any lone pair of electrons. It is a AB4 type molecule. Since there is no lone pair on the central atom, to minimize the repulsion, they form a tetrahedral geometry. So the bond angle between two atoms is 109.50.

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Chapter 10 Solutions

General Chemistry

Ch. 10.6 - Prob. 1RCCh. 10.6 - Prob. 2RCCh. 10.6 - Prob. 1PECh. 10 - Prob. 10.1QPCh. 10 - Prob. 10.2QPCh. 10 - 10.3 How many atoms arc directly bonded to the...Ch. 10 - 10.4 Discuss the basic features of the VSEPR...Ch. 10 - 10.5 In the trigonal bipyramidal arrangement, why...Ch. 10 - 10.6 The geometry of CH4 could be square planar,...Ch. 10 - Prob. 10.7QPCh. 10 - Prob. 10.8QPCh. 10 - Prob. 10.9QPCh. 10 - Prob. 10.10QPCh. 10 - 10.11 Describe the geometry around each of the...Ch. 10 - 10.12 Which of these species are tetrahedral?...Ch. 10 - 10.13 Define dipole moment. What are the units and...Ch. 10 - 10.14 What is the relationship between the dipole...Ch. 10 - 10.15 Explain why an atom cannot have a permanent...Ch. 10 - 10.16 The bonds in beryllium hydride (BeH2)...Ch. 10 - 10.17 Referring to Table 10.3. arrange the...Ch. 10 - 10.18 The dipole moments of the hydrogen halides...Ch. 10 - 10.19 List these molecules in order of increasing...Ch. 10 - 10.20 Docs the molecule OCS have a higher or lower...Ch. 10 - 10.21 Which of these molecules has a higher dipole...Ch. 10 - 10.22 Arrange these compounds in order of...Ch. 10 - 10.23 What is valence bond theory? How does it...Ch. 10 - 10.24 Use valence bond theory to explain the...Ch. 10 - 10.25Draw a potential energy curve for the bond...Ch. 10 - 10.26 What is the hybridization of atomic...Ch. 10 - 10.27 How does a hybrid orbital differ from a pure...Ch. 10 - 10.28 What is the angle between these two hybrid...Ch. 10 - 10.29 How would you distinguish between a sigma...Ch. 10 - 10.30 Which of these pairs of atomic orbitals of...Ch. 10 - 10.31 The following potential energy curve...Ch. 10 - 10.32 What is the hybridization state of Si in...Ch. 10 - 10.33 Describe the change in hybridization (if...Ch. 10 - 10.34 Consider the reaction Describe the changes...Ch. 10 - 10.35 What hybrid orbitals are used by nitrogen...Ch. 10 - Prob. 10.36QPCh. 10 - 10.37 Specify which hybrid orbitals are used by...Ch. 10 - 10.38 What is the hybridization state of the...Ch. 10 - 10.39 The allene molecule H2C=C=CH2 is linear (the...Ch. 10 - 10.40 Describe the hybridization of phosphorus in...Ch. 10 - 10.41 How many sigma bonds and pi bonds are there...Ch. 10 - 10.42 How many pi bonds and sigma bonds are there...Ch. 10 - 10.43 Give the formula of a cation comprised of...Ch. 10 - 10.44 Give the formula of an anion comprised of...Ch. 10 - 10.45 What is molecular orbital theory? How does...Ch. 10 - 10.46 Define these terms: bonding molecular...Ch. 10 - 10.47 Sketch the shapes of these molecular...Ch. 10 - 10.48 Explain the significance of bond order. Can...Ch. 10 - 10.49 Explain in molecular orbital terms the...Ch. 10 - Prob. 10.50QPCh. 10 - Prob. 10.51QPCh. 10 - Prob. 10.52QPCh. 10 - Prob. 10.53QPCh. 10 - Prob. 10.54QPCh. 10 - Prob. 10.55QPCh. 10 - 10.56 Compare the Lewis and molecular orbital...Ch. 10 - Prob. 10.57QPCh. 10 - 10.58 Compare the relative stability of these...Ch. 10 - Prob. 10.59QPCh. 10 - Prob. 10.60QPCh. 10 - Prob. 10.61QPCh. 10 - Prob. 10.62QPCh. 10 - Prob. 10.63QPCh. 10 - Prob. 10.64QPCh. 10 - Prob. 10.65QPCh. 10 - Prob. 10.66QPCh. 10 - Prob. 10.67QPCh. 10 - Prob. 10.68QPCh. 10 - 10.69 Draw Lewis structures and give the other...Ch. 10 - Prob. 10.70QPCh. 10 - Prob. 10.71QPCh. 10 - Prob. 10.72QPCh. 10 - Prob. 10.73QPCh. 10 - Prob. 10.74QPCh. 10 - Prob. 10.75QPCh. 10 - Prob. 10.76QPCh. 10 - Prob. 10.77QPCh. 10 - Prob. 10.78QPCh. 10 - Prob. 10.79QPCh. 10 - Prob. 10.80QPCh. 10 - Prob. 10.81QPCh. 10 - Prob. 10.82QPCh. 10 - Prob. 10.83QPCh. 10 - 10.84 The ionic character of the bond in a...Ch. 10 - Prob. 10.85QPCh. 10 - 10.86 Aluminum trichloride (AlCl3) is an...Ch. 10 - Prob. 10.87QPCh. 10 - Prob. 10.88QPCh. 10 - 10.90 Progesterone is a hormone responsible for...Ch. 10 - Prob. 10.91SPCh. 10 - Prob. 10.92SPCh. 10 - Prob. 10.93SPCh. 10 - 10.94 The molecule benzyne (C6H4) is a very...Ch. 10 - Prob. 10.95SPCh. 10 - 10.96 As mentioned in the chapter, the Lewis...Ch. 10 - Prob. 10.97SPCh. 10 - Prob. 10.98SPCh. 10 - Prob. 10.99SPCh. 10 - Prob. 10.100SPCh. 10 - Prob. 10.101SPCh. 10 - Prob. 10.102SP
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