INTOR TO CHEMISTRY LLF
5th Edition
ISBN: 9781264501731
Author: BAUER
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 10, Problem 142QP
Interpretation Introduction
Interpretation:
The increasing order of boiling points for given substances is to be predicted.
Concept Introduction:
The boiling point of a liquid is the temperature at which the vapor pressure of that liquid becomes equal to the surrounding pressure. At the boiling point, the liquid changes its state to vapor. The boiling point depends on the intermolecular forces present in the liquid. The more the intermolecular forces present, the higher is the boiling point of the liquid.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Based on the type or types of intermolecular forces, predictthe substance in each pair that has the higher boiling point:(a) propane 1C3H82 or n-butane 1C4H102, (b) diethyl ether1CH3CH2OCH2CH32 or 1-butanol 1CH3CH2CH2CH2OH2,(c) sulfur dioxide 1SO22 or sulfur trioxide 1SO32, (d) phosgene1Cl2CO2 or formaldehyde 1H2CO2.
Fill out this table. Once that is done, predict the order of the boiling points from lowest to the
highest.
Substance
ethanol
1-butanol
1-propanol C3H7OH
n-pentane
methanol
Formula
n-hexane
C₂H5OH
C4H9OH
C5H12
CH3OH
C6H14
H₂C.
Structural Formulas
CH₂
OH
out the
Molecular
Weight
Hydrogen
Bond
(Yes or No)
dab
Describe the changes (if any) in potential energy and in ki-netic energy among the molecules when gaseous PCl₃ condenses to a liquid at a fixed temperature.
Chapter 10 Solutions
INTOR TO CHEMISTRY LLF
Ch. 10 - How do the properties of liquids and solid differ,...Ch. 10 - Prob. 2QCCh. 10 - Prob. 3QCCh. 10 - Prob. 4QCCh. 10 - Prob. 1PPCh. 10 - Prob. 2PPCh. 10 - Prob. 3PPCh. 10 - Prob. 4PPCh. 10 - Which has the stronger London dispersion forces,...Ch. 10 - Prob. 6PP
Ch. 10 - Prob. 7PPCh. 10 - Prob. 8PPCh. 10 - Prob. 9PPCh. 10 - Prob. 10PPCh. 10 - Prob. 11PPCh. 10 - Prob. 12PPCh. 10 - Prob. 13PPCh. 10 - Prob. 14PPCh. 10 - Prob. 15PPCh. 10 - Prob. 1QPCh. 10 - Match the key terms with the description provided....Ch. 10 - Prob. 3QPCh. 10 - Prob. 4QPCh. 10 - Prob. 5QPCh. 10 - Prob. 6QPCh. 10 - Prob. 7QPCh. 10 - Prob. 8QPCh. 10 - Prob. 9QPCh. 10 - Prob. 10QPCh. 10 - Prob. 11QPCh. 10 - Prob. 12QPCh. 10 - Prob. 13QPCh. 10 - Prob. 14QPCh. 10 - Prob. 15QPCh. 10 - Prob. 16QPCh. 10 - Prob. 17QPCh. 10 - Prob. 18QPCh. 10 - Prob. 19QPCh. 10 - Prob. 20QPCh. 10 - Prob. 21QPCh. 10 - Prob. 22QPCh. 10 - Prob. 23QPCh. 10 - Prob. 24QPCh. 10 - Prob. 25QPCh. 10 - Prob. 26QPCh. 10 - Prob. 27QPCh. 10 - Prob. 28QPCh. 10 - Prob. 29QPCh. 10 - Prob. 30QPCh. 10 - Prob. 31QPCh. 10 - Prob. 32QPCh. 10 - Prob. 33QPCh. 10 - Prob. 34QPCh. 10 - Calculate the amount of heat required when 15.0 g...Ch. 10 - What is the amount of heat required to convert 105...Ch. 10 - Calculate the heat absorbed when 542 g of ice at...Ch. 10 - Prob. 38QPCh. 10 - Prob. 39QPCh. 10 - Calculated the heat released when 84.6 g of...Ch. 10 - Prob. 41QPCh. 10 - Prob. 42QPCh. 10 - Prob. 43QPCh. 10 - Prob. 44QPCh. 10 - Prob. 45QPCh. 10 - Prob. 46QPCh. 10 - Prob. 47QPCh. 10 - Prob. 48QPCh. 10 - Prob. 49QPCh. 10 - Prob. 50QPCh. 10 - Prob. 51QPCh. 10 - Prob. 52QPCh. 10 - Prob. 53QPCh. 10 - Prob. 54QPCh. 10 - Prob. 55QPCh. 10 - Prob. 56QPCh. 10 - Prob. 57QPCh. 10 - Prob. 58QPCh. 10 - Prob. 59QPCh. 10 - Prob. 60QPCh. 10 - Prob. 61QPCh. 10 - Prob. 62QPCh. 10 - Prob. 63QPCh. 10 - Prob. 64QPCh. 10 - Prob. 65QPCh. 10 - Prob. 66QPCh. 10 - Prob. 67QPCh. 10 - Prob. 68QPCh. 10 - Prob. 69QPCh. 10 - Prob. 70QPCh. 10 - Prob. 71QPCh. 10 - Prob. 72QPCh. 10 - Prob. 73QPCh. 10 - Prob. 74QPCh. 10 - Prob. 75QPCh. 10 - Prob. 76QPCh. 10 - Prob. 77QPCh. 10 - Prob. 78QPCh. 10 - Prob. 79QPCh. 10 - Prob. 80QPCh. 10 - Prob. 81QPCh. 10 - Prob. 82QPCh. 10 - Prob. 83QPCh. 10 - Prob. 84QPCh. 10 - Prob. 85QPCh. 10 - Prob. 86QPCh. 10 - Prob. 87QPCh. 10 - Prob. 88QPCh. 10 - Prob. 89QPCh. 10 - Prob. 90QPCh. 10 - Prob. 91QPCh. 10 - Prob. 92QPCh. 10 - Prob. 93QPCh. 10 - Prob. 94QPCh. 10 - Prob. 95QPCh. 10 - Prob. 96QPCh. 10 - Prob. 97QPCh. 10 - Prob. 98QPCh. 10 - Prob. 99QPCh. 10 - Prob. 100QPCh. 10 - Prob. 101QPCh. 10 - Prob. 102QPCh. 10 - Prob. 103QPCh. 10 - Prob. 104QPCh. 10 - Prob. 105QPCh. 10 - Prob. 106QPCh. 10 - Prob. 107QPCh. 10 - Prob. 108QPCh. 10 - Prob. 109QPCh. 10 - Prob. 110QPCh. 10 - Prob. 111QPCh. 10 - Prob. 112QPCh. 10 - Prob. 113QPCh. 10 - Prob. 114QPCh. 10 - Prob. 115QPCh. 10 - Prob. 116QPCh. 10 - Prob. 117QPCh. 10 - Prob. 118QPCh. 10 - Prob. 119QPCh. 10 - Prob. 120QPCh. 10 - Prob. 121QPCh. 10 - Prob. 122QPCh. 10 - Prob. 123QPCh. 10 - Prob. 124QPCh. 10 - Prob. 125QPCh. 10 - Prob. 126QPCh. 10 - Prob. 127QPCh. 10 - Prob. 128QPCh. 10 - Prob. 129QPCh. 10 - Prob. 130QPCh. 10 - Prob. 131QPCh. 10 - Prob. 132QPCh. 10 - Prob. 133QPCh. 10 - Prob. 134QPCh. 10 - Prob. 135QPCh. 10 - Prob. 136QPCh. 10 - Prob. 137QPCh. 10 - Prob. 138QPCh. 10 - Prob. 139QPCh. 10 - Prob. 140QPCh. 10 - Prob. 141QPCh. 10 - Prob. 142QPCh. 10 - Prob. 143QPCh. 10 - Prob. 144QPCh. 10 - Prob. 145QPCh. 10 - Prob. 146QPCh. 10 - Prob. 147QPCh. 10 - Prob. 148QPCh. 10 - Prob. 149QPCh. 10 - Prob. 150QPCh. 10 - Prob. 151QPCh. 10 - Prob. 152QPCh. 10 - Prob. 153QPCh. 10 - Prob. 154QP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- For each of the following pairs, choose the member with the lower boiling point. Explain your reason in each case. (a) NaCl or PCl3 (b) NH3 or AsH3 (c) C3H7OH or C2H5OCH3 (d) HI(g) or HCl(g)arrow_forwardThe compounds ethanol (C2H5OH) and dimethyl ether (CH3OCH3) have the same molecular formula. Which is expected to have the higher surface tension? Why?arrow_forwardExplain why liquids assume the shape of any container into which they are poured, whereas solids are rigid and retain their shape.arrow_forward
- Which member of each of the following pairs of compounds has the higher boiling point? (a) O2 or N2 (b) SO2 or CO2 (c) HF or HI (d) SiH4 or GeH4arrow_forwardDescribe the formation of hydrogen bonds in propanol, CH3CH2CH2OH. Represent possible hydrogen bonding structures in propanol by using structural formulas and the conventional notation for a hydrogen bond.arrow_forwardWhich would you expect to have the higher fusion enthalpy, N2 or I2? Explain your choice.arrow_forward
- Use Figure 11.7 to estimate the boiling point of diethyl ether, (C2H5)2O, under an external pressure of 470 mmHg.arrow_forwardUse Figure 11.7 to estimate the boiling point of carbon tetrachloride, CCl4, under an external pressure of 250 mmHg.arrow_forwardConsider the iodine monochloride molecule, ICI. Because chlorine is more electronegative than iodine, this molecule is a dipole. How would you expect iodine monochloride molecules in the gaseous state to orient themselves with respect to each other as the sample is cooled and the molecules begin to aggregate? Sketch the orientation you would expect.arrow_forward
- Which of the following compounds would be expected to form intermolecular hydrogen bonds in the liquid state? (a) H2Se (b) HCO2H (formic acid) (c) HI (d) acetone, (CH3)2COarrow_forwardWhich of the following compounds would you expect to exhibit only London forces? a potassium chloride, KCl b c silicon tetrafluoride, SiF4 d phosphorus pentachloride, PCl5arrow_forwardFor the hydrogen halides and the noble gases, we have the following boiling points: Halogen Family, C Noble Gases, C HF, 19 Nc, 246 HCl, 115 Ar, 186 HBr, 67 Kr, 152 HI, 35 Xe, 108 Account for the following: a The general trend in the boiling points of the hydrides and the noble gases. b The unusual boiling point of hydrogen fluoride. c The observation that the hydrogen halides have boiling points that are significantly higher than the noble gases.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Chemistry by OpenStax (2015-05-04)ChemistryISBN:9781938168390Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark BlaserPublisher:OpenStax
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
Introduction to General, Organic and Biochemistry
Chemistry
ISBN:9781285869759
Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar Torres
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry by OpenStax (2015-05-04)
Chemistry
ISBN:9781938168390
Author:Klaus Theopold, Richard H Langley, Paul Flowers, William R. Robinson, Mark Blaser
Publisher:OpenStax
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
General Chemistry - Standalone book (MindTap Cour...
Chemistry
ISBN:9781305580343
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Publisher:Cengage Learning
Liquids: Crash Course Chemistry #26; Author: Crash Course;https://www.youtube.com/watch?v=BqQJPCdmIp8;License: Standard YouTube License, CC-BY
Chemistry of Group 16 elements; Author: Ch-11 Chemical Engg, Chemistry and others;https://www.youtube.com/watch?v=5B1F0aDgL6s;License: Standard YouTube License, CC-BY